How much mass-energy (in joules) is contained in a peanut weighing 0.1 ounce? How much mass-energy do you gain by eating 10 ounces of peanuts? Compare this with the food energy content of peanuts, about 100 kcal per ounce.
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How much mass-energy (in joules) is contained in a peanut weighing 0.1 ounce? How much mass-energy do you gain by eating 10 ounces of peanuts? Compare this with the food energy content of peanuts, about 100 kcal per ounce.
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- Suppose that you have found a way to convert the rest energy of any type of matter directly to usable energy with an efficiency of 85.0%. How many liters of water would be sufficient fuel to very slowly push the Moon 2.90 mm away from the Earth? The density of water is pwater = 1.00kg/liter, the Earth's mass is Mearth = 5.97 x 1024 kg, the Moon's mass is Mmoon = 7.36 x 10²² kg, and the separation of the Earth and Moon is deM = 3.84 × 10% m. water: LitersQuestion 8 The star Betelgeuse is about 520 light-years away, If the speed of light were twice its present value, how far away would Betelgeuse be? O 2080 ly O 560 ly O 260 ly O 1040 ly O 130 ly Question 9 Which of the following is the reason for an ocean of water under Europa's frozen surface? O Europa had many icy comets crash into the surface bring water to the moon and melting the water as it fell into the core. O Furopa formed with an unusual amount of liquid water in the core and the coldness of space wasn't able to freeze it. O upiter's strong gravitational force is causing Europa to flex in its orbit, leading to an increase in internal heating. O Europa's close proximity to Jupiter puts it into a gravitational tug-of-war with Jupiter's targest moon Ganymede. Question 10 How was Neptune discovered? O When a large comet broke up and hit the planet, the explosion was seen from Earth-based telescopes O From a large sky survey that identified the "blue-green" planet. O By watching…Consider the equation for kinetic energy: KE = 1/2mv^2 = 1/2 * m * v^2. If I ask you to take the derivative of kinetic energy, you should ask "the derivative with respect to what?" a) Suppose mass m is constant. Compute the derivative of KE with respect to v, (d(KE)/dv). b) Who takes derivatives with respect to velocity? No one. Except you, just now. Sorry. The rate of change of energy with respect to time is more important: it is the Power. Now, consider velocity v to be a function of time, v(t). We will rewrite KE showing this time dependance: KE= 1/2 * m * v(t)^2. Show that (d(KE)/dt) = F(t)v(t). Hint: use Newton's second law, F = ma, to simplify. c) In the computation above, we assumed m was constant, and v was changing in time. Think of a physical situation in which both m and v are varying in time. d) Compute the Power when both mass and velocity are changing in time. (First rewrite KE(t) showing time dependence, then compute (d(KE)/dt).
- Find the rest energy, in terajoules, of a 19.9 g piece of chocolate. 1 TJ is equal to 10'2 J. rest energy: TJThe escape velocity from a massive object is the speed needed to reach an infinite distance from it and have just slowed to a stop, that is, to have just enough kinetic energy to climb out of the gravitational potential well and have none left. You can find the escape velocity by equating the total kinetic and gravitational potential energy to zero E=12mv2esc−GmM/r=0E=12mvesc2−GmM/r=0 vesc=2GM/r−−−−−−√vesc=2GM/r where GG is Newton's constant of gravitation, MM is the mass of the object from which the escape is happening, and rr is its radius. This is physics you have seen in the first part of the course, and you should be able to use it to find an escape velocity from any planet or satellite. For the Earth, for example the escape velocity is about 11.2 km/s, and for the Moon it is 2.38 km/s. A very important point about escape velocity: it does not depend on what is escaping. A spaceship or a molecule must have this velocity or more away from the center of the planet to be free…By converting the mass of one person (68 kg) completely into energy, how much energy may be released?