How much heat would be required to convert 390 g of solid benzene, C6H6 (s), at 5.5°C into benzene vapor, C6H6 (g), at 120.0°C? mp of C6H6 (s) = 5.5oC molar heat of fusion at 5.5°C = 9.92 kJ/mol bp of C6H6 (l) = 80.1°C molar heat of vaporization at 80.1°C = 30.8 kJ/mol molar heat capacity of C6H6 (l) = 136 J/mol-°C molar heat capacity of C6H6 (g) = 81.6 J/mol-°C 106 kJ 158 kJ 53.kJ 262.kJ 5049 kJ
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
-
How much heat would be required to convert 390 g of solid benzene, C6H6 (s), at 5.5°C into benzene vapor, C6H6 (g), at 120.0°C?
mp of C6H6 (s) = 5.5oC molar heat of fusion at 5.5°C = 9.92 kJ/mol
bp of C6H6 (l) = 80.1°C molar heat of vaporization at 80.1°C = 30.8 kJ/mol
molar heat capacity of C6H6 (l) = 136 J/mol-°C
molar heat capacity of C6H6 (g) = 81.6 J/mol-°C
106 kJ
158 kJ
53.kJ
262.kJ
5049 kJ
Trending now
This is a popular solution!
Step by step
Solved in 4 steps