How much heat must be absorbed by 400 kilograms of water from 2°C to 25°C?
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A: Q =mc(∆T) =(0.9)(4.186)(25-0) = 94.185 kJ = 94185 J
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A: Given Mass of ice is m=11 kg Specific heat of water is cwater = 4186 J/kg C° Specific heat of…
How much heat must be absorbed by 400 kilograms of water from 2°C to 25°C?
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