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- The heat energy transferred to a system depends on three factors temperature change, the mass of the system, and the substance undergoing the temperature change.
- The quantitative relationship between heat energy and the three factors is given by,
Here m is the mass of the system, c is the specific heat, and ΔT is the change in temperature due to the energy change.
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- The world's deepest gold mine, which is located in South Africa, is over 5.1 km deep. Every day, the mine transfers enough energy by heat to the mine's cooling systems to melt 348114 kg of ice at 0.0 degrees Celsius. If the energy output from the mine is increased by 9.6 percent, to what final temperature will the 348114 kg of ice-cold water be heated? Latent Heat of fusion of Ice-3.33 × 105 J/kg Specific heat capacity of Water = 4186J/(kg. °C)Arelyz and Hyeonggyun drop a 378.0-g piece of metal at 100.0°C into 447.0 g of water at 20.0°C. The final temperature of the system is measured to be 50.0°C. What is the specific heat of the metal in J/kgK, assuming no heat is exchanged with the surroundings or the cup containing the water? The specific heat of water is 4190 J/(kg K).The intensity of solar radiation above the earth’s atmosphere is about 1300 W/m2. The earth’s average surface temperature is relatively constant over geological time spans, so the energy the earth receives from the sun must be balanced by energy the earth reradiates in all directions into space. If the earth were to have a uniform temperature over its entire surface, what would the temperature be?
- Problem 2: 0.4 kg of ice at – 10°C are mixed with 0.2 kg of water at 50°C. The water and ice are mixed in a calorimeter so that no heat escapes the system. The specific heat of ice is c; = 2090 J/(kg.°C), the la- tent heat of fusion of water is Lf = 3.33× 10° J/kg, and the specific heat of water is cu = 4186 J/(kg-°C). (a) What is the final temperature of the system? (b) How many kg of ice remain in the end? (c) How many kg of water remain in the end?One strategy when on a diet is to drink ice water. The body must burn calories to warm the water from 32 °F to a body temperature of 98.6 °F. Assume a dieter drinks 2.4 kg (2.4 L) of ice water every day. How much energy, in Cal, does the dieter's body need to provide in order to warm the 2.4-L-water. (The specific heat of water is 4186 J/kg • °C; 1J = 0.000239 Cal.) Show your work.A student measures the following data in a calorimetry experiment designed to determine the specific heat of aluminum. (Do not assume atmospheric pressure.) Initial temperature of water and calorimeter: 70°C Mass of water: 0.400 kg Mass of calorimeter: 0.040 kg Specific heat of calorimeter: 0.63 kJ/kg · °C Initial temperature of aluminum: 26.6°C Mass of aluminum: 0.200 kg Final temperature of mixture: 65.8°C Use these data to determine the specific heat of aluminum.