How much energy is released from the following fission event? 232 Pu+n→ ¹331 + 103Nb +2n+y Given: mass of Pu-239=239.0522 AMU mass of n = 1.0087 AMU mass of 1-135= 134.9100 AMU mass of Nb-103 102.9091 AMU.

How much energy is released from the following fission event? 232 Pu+n→ ¹331 + 103Nb +2n+y Given: mass of Pu-239=239.0522 AMU mass of n = 1.0087 AMU mass of 1-135= 134.9100 AMU mass of Nb-103 102.9091 AMU.

College Physics

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Author:Paul Peter Urone, Roger Hinrichs

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Chapter32: Medical Applications Of Nuclear Physics

Section: Chapter Questions

Problem 44PE: (a) Calculate the energy released in the neutroninduced fission reaction n+235U92Kr+142Ba+2n, given...

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Question

How much energy is released from the following fission event?
232 Pu+n→ ¹331 + 103Nb + 2n+y
Given:
mass of Pu-239=239.0522 AMU
mass of n = 1.0087 AMU
mass of 1-135= 134.9100 AMU
mass of Nb-103= 102.9091 AMU.

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