Calculate the recoil energy of 208Pb in the c.m. decay 212Po → 208Pb+α.
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4 Calculate the recoil energy of 208Pb in the c.m. decay 212Po → 208Pb+α.
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- 1) For each of the following reactions work out the fastest interaction through which the conservation laws allow it to proceed. Explain your answers. If the reaction is forbidden by all interactions explain why: -+ a. pn++μ+ +μ¯ b. Aºp+e¯ c. μ΄ →e + V d. p+p→y+Y e. Kºn++ π + π° +7° f. π+pAº + Kº g. Aºn+p h. pnº+e+ + ve i. n→p+e+V₂A beam of 8.47-MeV protons is incident on a target of 27/13 Al. Those protons that collide produce the reaction shown below. p + 27 13 Al → 27 14 Si + n ( 27 14 Si has a mass of 26.986721 u.) Neglecting any recoil of the product nucleus, determine the kinetic energy of the emerging neutrons. Answer:_____MeV Sorry the formatting is kinda off, im not sure how to fix it. Thank you!A free neutron decays into a proton plus an electron: n -> p + e- . This is called beta decay. a. Is energy released or absorbed in this reaction? b. Calculate the energy.