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How many moles of oxygen atoms are present in 5.148 kg of calcium oxalate? O 6.594 x 102 O 1.608 x 102 O 4.019 x 101 O 4.019 x 10-2 O 1.608 x 10-4

How many moles of oxygen atoms are present in 5.148 kg of calcium oxalate? O 6.594 x 102 O 1.608 x 102 O 4.019 x 101 O 4.019 x 10-2 O 1.608 x 10-4

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** How many moles of oxygen atoms are present in 5.148 kg of calcium oxalate? **Answer Choices:** - 6.594 x 10² - 1.608 x 10² - 4.019 x 10¹ - 4.019 x 10⁻² - 1.608 x 10⁻⁴ **Explanation of Answer Choices:** The image shows a set of multiple-choice answers to a question about calculating the number of moles of oxygen atoms in a given mass of calcium oxalate. - The first option is \(6.594 \times 10^2\) - The second option is \(1.608 \times 10^2\) - The third option is \(4.019 \times 10^1\) - The fourth option (highlighted/selected) is \(4.019 \times 10^{-2}\) - The fifth option is \(1.608 \times 10^{-4}\) This type of question often requires knowledge of molar masses, Avogadro's number, and stoichiometric conversions from mass to moles. It is important to use the molecular formula of calcium oxalate, \( \text{CaC}_2\text{O}_4 \), to determine the number of oxygen atoms per formula unit and to carry out the appropriate calculations based on the given mass.
Transcribed Image Text:**Question:** How many moles of oxygen atoms are present in 5.148 kg of calcium oxalate? **Answer Choices:** - 6.594 x 10² - 1.608 x 10² - 4.019 x 10¹ - 4.019 x 10⁻² - 1.608 x 10⁻⁴ **Explanation of Answer Choices:** The image shows a set of multiple-choice answers to a question about calculating the number of moles of oxygen atoms in a given mass of calcium oxalate. - The first option is \(6.594 \times 10^2\) - The second option is \(1.608 \times 10^2\) - The third option is \(4.019 \times 10^1\) - The fourth option (highlighted/selected) is \(4.019 \times 10^{-2}\) - The fifth option is \(1.608 \times 10^{-4}\) This type of question often requires knowledge of molar masses, Avogadro's number, and stoichiometric conversions from mass to moles. It is important to use the molecular formula of calcium oxalate, \( \text{CaC}_2\text{O}_4 \), to determine the number of oxygen atoms per formula unit and to carry out the appropriate calculations based on the given mass.
### Chemistry Question: Mg(OH)₂ Sample Analysis **Question:** A 789.1 ng sample of magnesium hydroxide contains what mass of hydroxide ions? **Answer Choices:** - \( \circ \) \( 5.412 \times 10^{-6} \) g - \( \circ \) \( 4.602 \times 10^{-7} \) g - \( \circ \) \( 3.978 \times 10^{8} \) g - \( \circ \) \( 2.301 \times 10^{-7} \) g - \( \circ \) \( 1.151 \times 10^{11} \) g Please review the calculations and stoichiometry principles involved in determining the mass of hydroxide ions from a given sample of magnesium hydroxide. Use the molecular weights and Avogadro's number to find the correct answer.
Transcribed Image Text:### Chemistry Question: Mg(OH)₂ Sample Analysis **Question:** A 789.1 ng sample of magnesium hydroxide contains what mass of hydroxide ions? **Answer Choices:** - \( \circ \) \( 5.412 \times 10^{-6} \) g - \( \circ \) \( 4.602 \times 10^{-7} \) g - \( \circ \) \( 3.978 \times 10^{8} \) g - \( \circ \) \( 2.301 \times 10^{-7} \) g - \( \circ \) \( 1.151 \times 10^{11} \) g Please review the calculations and stoichiometry principles involved in determining the mass of hydroxide ions from a given sample of magnesium hydroxide. Use the molecular weights and Avogadro's number to find the correct answer.
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