What is the mass in grams of H₂ that can be formed from 88.2 grams of NH, in the following reaction? 2 NH₂(g) → 3 H₂(g) + N₂(g)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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**Problem Description:**

What is the mass in grams of \( \text{H}_2 \) that can be formed from 88.2 grams of \( \text{NH}_3 \) in the following reaction?

\[ 2 \, \text{NH}_3(g) \rightarrow 3 \, \text{H}_2(g) + \text{N}_2(g) \]

**Explanation:**

This problem involves a stoichiometric calculation that requires determining the mass of hydrogen gas (\( \text{H}_2 \)) produced from a given mass of ammonia (\( \text{NH}_3 \)). The balanced chemical equation provided is crucial for understanding the molar relationships between reactants and products. 

To find the solution:

1. Calculate the molar mass of \( \text{NH}_3 \).
2. Determine the moles of \( \text{NH}_3 \) available.
3. Use the stoichiometry of the reaction to find the moles of \( \text{H}_2 \) produced.
4. Convert moles of \( \text{H}_2 \) to grams using its molar mass.

This type of calculation is fundamental in chemistry for predicting product formation in chemical reactions.
Transcribed Image Text:**Problem Description:** What is the mass in grams of \( \text{H}_2 \) that can be formed from 88.2 grams of \( \text{NH}_3 \) in the following reaction? \[ 2 \, \text{NH}_3(g) \rightarrow 3 \, \text{H}_2(g) + \text{N}_2(g) \] **Explanation:** This problem involves a stoichiometric calculation that requires determining the mass of hydrogen gas (\( \text{H}_2 \)) produced from a given mass of ammonia (\( \text{NH}_3 \)). The balanced chemical equation provided is crucial for understanding the molar relationships between reactants and products. To find the solution: 1. Calculate the molar mass of \( \text{NH}_3 \). 2. Determine the moles of \( \text{NH}_3 \) available. 3. Use the stoichiometry of the reaction to find the moles of \( \text{H}_2 \) produced. 4. Convert moles of \( \text{H}_2 \) to grams using its molar mass. This type of calculation is fundamental in chemistry for predicting product formation in chemical reactions.
**Question:**

How many moles of H₂O can be formed from 7.00 × 10²³ molecules of NH₃ from the following equation?

\[ 4 \text{ NH}_3(g) + 5 \text{ O}_2(g) \rightarrow 4 \text{ NO}(g) + 6 \text{ H}_2\text{O}(g) \]

**Explanation:**

This chemical equation represents the reaction between ammonia (NH₃) and oxygen (O₂) to produce nitrogen monoxide (NO) and water (H₂O). The stoichiometric coefficients indicate the mole ratio of the reactants and products involved in the reaction:

- 4 moles of NH₃ react with 5 moles of O₂
- This produces 4 moles of NO and 6 moles of H₂O

Given 7.00 × 10²³ molecules of NH₃, we need to calculate the corresponding moles of H₂O. Using Avogadro's number (6.022 × 10²³ molecules/mol), we can determine the number of moles of NH₃ and then use the mole ratio to find the moles of H₂O produced.
Transcribed Image Text:**Question:** How many moles of H₂O can be formed from 7.00 × 10²³ molecules of NH₃ from the following equation? \[ 4 \text{ NH}_3(g) + 5 \text{ O}_2(g) \rightarrow 4 \text{ NO}(g) + 6 \text{ H}_2\text{O}(g) \] **Explanation:** This chemical equation represents the reaction between ammonia (NH₃) and oxygen (O₂) to produce nitrogen monoxide (NO) and water (H₂O). The stoichiometric coefficients indicate the mole ratio of the reactants and products involved in the reaction: - 4 moles of NH₃ react with 5 moles of O₂ - This produces 4 moles of NO and 6 moles of H₂O Given 7.00 × 10²³ molecules of NH₃, we need to calculate the corresponding moles of H₂O. Using Avogadro's number (6.022 × 10²³ molecules/mol), we can determine the number of moles of NH₃ and then use the mole ratio to find the moles of H₂O produced.
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