How many moles of Mg+2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? First we have to convert moles into equivalents 3 Mg+2 + 2 PO4³ -3 Mg3(PO4)2 1 mol = 1 1 mol MP = m equivalents mol Mg+2

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How many moles of Mg+2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? (answer is 1.80 x 10-2 mol)

Mg3(PO4)2 ® + 2 PO4 -3

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How many moles of Mg+2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ?
First we have to convert moles into equivalents
Mg3(PO4)2
→ 3 Mg+2 + 2 PO4³
1 mol = I
1 mol MP = m
(6.00 x 10-3 L)(-
|j
a. 250.
b. 100.0
j. 1 k. 6.00 x 10-3
q. 7.65 x 10-10
X. 10³
r. 2.63
y. 95.21
equivalents
mol MP)(-
c. 2
+2
mol Mg¹2
I. 3.60 x 10-²
z. 10
d. 30.00
s. 7.89
eq
mol Mg¹2
+2
e. 6
m. 6.00 x 10-²
t. 5.26
mol MP
f. 24
n. 5
u. 1012
eq MP (-
= p
h. 36
g. 3
o. 3.0 x 10-²
V. 10⁹
i. 18.0
p. 1.80 x 10-²
W. 106
mol
eq
mol Mg+2
=
Transcribed Image Text:How many moles of Mg+2 in 6.00 mL of a 6.0 N Mg3(PO4)2 solution ? First we have to convert moles into equivalents Mg3(PO4)2 → 3 Mg+2 + 2 PO4³ 1 mol = I 1 mol MP = m (6.00 x 10-3 L)(- |j a. 250. b. 100.0 j. 1 k. 6.00 x 10-3 q. 7.65 x 10-10 X. 10³ r. 2.63 y. 95.21 equivalents mol MP)(- c. 2 +2 mol Mg¹2 I. 3.60 x 10-² z. 10 d. 30.00 s. 7.89 eq mol Mg¹2 +2 e. 6 m. 6.00 x 10-² t. 5.26 mol MP f. 24 n. 5 u. 1012 eq MP (- = p h. 36 g. 3 o. 3.0 x 10-² V. 10⁹ i. 18.0 p. 1.80 x 10-² W. 106 mol eq mol Mg+2 =
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