### Calculation of Moles of Ethanol (C₂H₅OH) in a Solution**Question:**What quantity in moles of \( \text{C}_2\text{H}_5\text{OH} \) are there in 63.4 mL of 0.250 M \( \text{C}_2\text{H}_5\text{OH} \)?**Solution:**1. **Understanding Molarity:** - Molarity (M) is defined as the number of moles of solute (in this case, \( \text{C}_2\text{H}_5\text{OH} \)) per liter of solution. - Given molarity (M) = 0.250 M, it means 0.250 moles of \( \text{C}_2\text{H}_5\text{OH} \) in 1 liter of the solution.2. **Volume Conversion:** - Volume given = 63.4 mL. - Convert milliliters (mL) to liters (L): \[ 63.4 \, \text{mL} = 63.4 \times 10^{-3} \, \text{L} \] \[ 63.4 \, \text{mL} = 0.0634 \, \text{L} \]3. **Calculate Moles:** - Use the formula to calculate the moles of solute: \[ \text{Moles of solute} = \text{Molarity} \times \text{Volume (in liters)} \] - Substituting the values: \[ \text{Moles of } \text{C}_2\text{H}_5\text{OH} = 0.250 \, \text{M} \times 0.0634 \, \text{L} \] \[ \text{Moles of } \text{C}_2\text{H}_5\text{OH} = 0.01585 \, \text{moles} \]**Answer:**There are \(0.01585\) moles of \( \text{C}_2\text{H}_5\text{OH} \) in 63

As we know that Molarity of a substance is defined as moles of solute in unit volume of solvent in…

Answered: 1 С̧ Н ОН? 2 5 2 5

1 С̧ Н ОН? 2 5 2 5

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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