How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H2SO.(aq) Al2(SO.)3(aq) + 3 H2(g) 7.20 mol Al mol H,SO, STARTING AMOUNT
How many moles of H2SO, are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H2SO.(aq) Al2(SO.)3(aq) + 3 H2(g) 7.20 mol Al mol H,SO, STARTING AMOUNT
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Transcription for Educational Website**
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**Stoichiometry Calculation for Aluminum and Sulfuric Acid Reaction**
**Objective**: Determine how many moles of \( \text{H}_2\text{SO}_4 \) are required to completely react with 7.20 moles of \( \text{Al} \) according to the balanced chemical reaction.
**Balanced Chemical Equation**:
\[
2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4 \text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3 \text{(aq)} + 3 \text{H}_2 \text{(g)}
\]
**Starting Amount**:
\[
7.20 \, \text{mol} \, \text{Al}
\]
**Calculation**:
\[
7.20 \, \text{mol} \, \text{Al} \times \left( \frac{\text{unknown}}{\text{unknown}} \right) = \, \text{mol} \, \text{H}_2\text{SO}_4
\]
**Interactive Elements**:
- **Add Factor**: \( \times \left( \right) \)
- **Delete**: Tool to remove entries
- **Answer**: Submit calculated results
- **Reset**: Start over the calculation process
**Available Inputs**:
- Atomic and molar masses in gram and mole conversions include:
- Numerical values like 26.98, 98.08, 342.14, 6.022 × 10²³
- Corresponding prefixes like mol Al, g Al, g \( \text{Al}_2(\text{SO}_4)_3 \), mol \( \text{H}_2\text{SO}_4 \), etc.
This educational tool is designed to facilitate learning of stoichiometry by allowing users to input values and calculate how many moles of one reactant are needed for complete reaction with another based on a balanced chemical equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faeef920a-b7fc-42c4-a405-16f92aebf3b1%2F4a1c5e60-0195-4bd5-85da-22947bf38177%2Fgkfj3b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
---
**Stoichiometry Calculation for Aluminum and Sulfuric Acid Reaction**
**Objective**: Determine how many moles of \( \text{H}_2\text{SO}_4 \) are required to completely react with 7.20 moles of \( \text{Al} \) according to the balanced chemical reaction.
**Balanced Chemical Equation**:
\[
2 \text{Al(s)} + 3 \text{H}_2\text{SO}_4 \text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3 \text{(aq)} + 3 \text{H}_2 \text{(g)}
\]
**Starting Amount**:
\[
7.20 \, \text{mol} \, \text{Al}
\]
**Calculation**:
\[
7.20 \, \text{mol} \, \text{Al} \times \left( \frac{\text{unknown}}{\text{unknown}} \right) = \, \text{mol} \, \text{H}_2\text{SO}_4
\]
**Interactive Elements**:
- **Add Factor**: \( \times \left( \right) \)
- **Delete**: Tool to remove entries
- **Answer**: Submit calculated results
- **Reset**: Start over the calculation process
**Available Inputs**:
- Atomic and molar masses in gram and mole conversions include:
- Numerical values like 26.98, 98.08, 342.14, 6.022 × 10²³
- Corresponding prefixes like mol Al, g Al, g \( \text{Al}_2(\text{SO}_4)_3 \), mol \( \text{H}_2\text{SO}_4 \), etc.
This educational tool is designed to facilitate learning of stoichiometry by allowing users to input values and calculate how many moles of one reactant are needed for complete reaction with another based on a balanced chemical equation.
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