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How many molecules are in 2.73g of NaCl?

How many molecules are in 2.73g of NaCl?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How many molecules are in 2.73g of NaCl?
### Chemistry Problems: Mole and Molecule Calculations #### Question 1: Mole Concept Confusion - **Statement**: "moles do not gave grams" #### Question 2: Molecule Count in Sodium Chloride (NaCl) - **Question**: How many molecules are in 2.73 g of NaCl? - **Options**: 1. 6.02 X 10^23 2. 2.8 X 10^22 3. 58 X 10^5 4. 2.73 X 10^22 #### Question 3: Reaction of Zinc Bromide with Reactants - **Question**: 200 g of zinc bromide reacts completely with excess to produce zinc nitrate and magnesium bromide. How much will be formed? - **Options** (Note: The options are not fully visible in the image and will require additional context): 1. 93.5 g zinc nitrate and 108.3 g of magnesium bromide 2. (additional options likely following the pattern but not visible) The first question presents a statement that seems to have an error ("moles do not gave grams" likely intends to convey that 'moles do not have grams'), which is crucial to address before moving to subsequent calculations and concepts. The subsequent questions ask learners to apply their knowledge of chemical stoichiometry and the mole concept to determine the number of molecules and the product masses in chemical reactions. ### Detailed Explanation of Graphs or Diagrams There are no graphs or diagrams in this image, only multiple-choice questions about stoichiometry and the mole concept. Each question is aimed at testing a specific aspect of students' understanding of chemical quantities and reactions. ### Educational Insight: To solve the questions related to the number of molecules: 1. Calculate the molar mass of NaCl (Sodium: 22.99 g/mol, Chlorine: 35.45 g/mol). 2. Convert grams to moles using the molar mass. 3. Use Avogadro's number (6.02 x 10^23) to convert moles to molecules. For reaction-based questions, balanced chemical equations and stoichiometric calculations are crucial. Make sure to refer to the molar ratios from the balanced equation to determine the mass of the products formed.
Transcribed Image Text:### Chemistry Problems: Mole and Molecule Calculations #### Question 1: Mole Concept Confusion - **Statement**: "moles do not gave grams" #### Question 2: Molecule Count in Sodium Chloride (NaCl) - **Question**: How many molecules are in 2.73 g of NaCl? - **Options**: 1. 6.02 X 10^23 2. 2.8 X 10^22 3. 58 X 10^5 4. 2.73 X 10^22 #### Question 3: Reaction of Zinc Bromide with Reactants - **Question**: 200 g of zinc bromide reacts completely with excess to produce zinc nitrate and magnesium bromide. How much will be formed? - **Options** (Note: The options are not fully visible in the image and will require additional context): 1. 93.5 g zinc nitrate and 108.3 g of magnesium bromide 2. (additional options likely following the pattern but not visible) The first question presents a statement that seems to have an error ("moles do not gave grams" likely intends to convey that 'moles do not have grams'), which is crucial to address before moving to subsequent calculations and concepts. The subsequent questions ask learners to apply their knowledge of chemical stoichiometry and the mole concept to determine the number of molecules and the product masses in chemical reactions. ### Detailed Explanation of Graphs or Diagrams There are no graphs or diagrams in this image, only multiple-choice questions about stoichiometry and the mole concept. Each question is aimed at testing a specific aspect of students' understanding of chemical quantities and reactions. ### Educational Insight: To solve the questions related to the number of molecules: 1. Calculate the molar mass of NaCl (Sodium: 22.99 g/mol, Chlorine: 35.45 g/mol). 2. Convert grams to moles using the molar mass. 3. Use Avogadro's number (6.02 x 10^23) to convert moles to molecules. For reaction-based questions, balanced chemical equations and stoichiometric calculations are crucial. Make sure to refer to the molar ratios from the balanced equation to determine the mass of the products formed.
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