The chemical formula for octane is:CH₂(CH₂) CH3Calculate the molar mass of octane.Round your answer to 1 decimal place.-1g-molx10Ś

Molar mass of a compound is defined as the mass of 1 mole of that substance and number of grams per…

Answered: d your answer to 1 decimal p g-mol -1

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Chemistry

d your answer to 1 decimal p g-mol -1

Introductory Chemistry: A Foundation

8th Edition

ISBN:9781285199030

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter6: Chemical Reactions: An Introduction

Section: Chapter Questions

Problem 58AP

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4-77 To convert 1 mol of iron(III) oxide to its elements requires 196.5 kcal: How many grams of iron can be produced if 156.0 kcal of heat is absorbed by a large-enough sample of iron(III) oxide?
A soft drink contains an unknown mass of citric acid, C3H5O(COOH)3. It requires 6.42 mL of 9.580 × 10−2-M NaOH to neutralize the citric acid in 10.0 mL of the soft drink. C3H5O(COOH)3(aq) + 3 NaOH(aq) → Na3C3H5O(COO)3(aq) + 3 H2O(ℓ) Determine which step in these calculations for the mass of citric acid in 1 mL soft drink is incorrect? Why? n (NaOH) = (6.42 mL)(1L/1000 mL)(9.580 × 10−2 mol/L) n (citric acid) = (6.15 × 10−4 mol NaOH) × (3 mol citric acid/1 mol NaOH) m (citric acid in sample) = (1.85 × 10−3 mol citric acid) × (192.12 g/mol citric acid) m (citric acid in 1 mL soft drink) = (0.354 g citric acid)/(10 mL soft drink) Determine the correct result.
35. For each of the following solutions, the mass of solute is given, followed by the total volume of the solution prepared. Calculate the molarity of each solution. a. 3.51 g NaCl: 25 mL c. 3.51 g NaCl: 75 mL b. 3.51 g NaCl; 50. mL d. 3.51 g NaCl; l.00 L
3.82 The particulate scale drawing shown depicts the products of a reaction between N2 and O2 molecules. (a) Draw a similar representation for the reactants that must have been present before the reaction took place. (b) Write a balanced chemical equation for the reaction, using the smallest possible whole number coefficients.
About 5 billion kilograms of benzene, C6H6, are made each year. Benzene is used as a starting material for many other compounds and as a solvent (although it is also a carcinogen, and its use is restricted). One compound that can be made from benzene is cyclohexane, C6H12. C6H6() + 3 H2(g) C6H12() rH = 206.7 kJ/mol-rxn; rS = 361.5 J/K mol-rxn Is this reaction predicted to be product-favored at equilibrium at 25 C? Is the reaction enthalpy- or entropy-driven?
3.115 The average person exhales 1.0 kg of carbon dioxide in a day. Describe how you would estimate the number of CO2 molecules exhaled per breath for this average person.
When corn is allowed to ferment, the fructose in the corn is converted to ethyl alcohol according to the following reaction C6H12O6(aq)2C2H5OH(l)+2CO2(g)(a) What volume of ethyl alcohol (d=0.789g/mL) is produced from one pound of fructose? (b) Gasohol can be a mixture of 10 mL ethyl alcohol and 90 mL of gasoline. How many grams of fructose are required to produce the ethyl alcohol in one gallon of gasohol?
3.83 For the reaction of nitrogen, N2, and hydrogen, H2, to form ammonia, NH3, a student is attempting to draw a particulate diagram, as shown below. Did the student draw a correct representation of the reaction? If not, what was the error the student made?
The chemical formula for t-butanol is: (CH), СОН Calculate the molar mass of t-butanol. Round your answer to 2 decimal places. - 1 g•mol x10 ?
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B. Percentage of Water in an Unknown Hydrate CUC2·X H20 UNKNOWN # mass of beaker and watchglass + unknown hydrate (before heating) 123.02 123.02 mass of beaker and watchglass 121.98 122.01 mass of unknown hydrate 122.81 122.78 mass of beaker and watchglass + anhydrous compound (after heating) nass of water (before heating - after heating) Show the calculation for the percentage of water for trial 1 (see Example Exercise 2). Percentage of water in the unknown hydrate Average percentage of water C. Water of Crystallization in an Unknown Hydrate 170.48 g/mol molar mass of anhydrous compound (AC) (see Instructor) percentage of water (see Procedure B) percentage of anhydrous compound (AC) Show the calculation for the water of crystallization (see Example Exercise 3). Water of crystallization НО AC• (Based on how rounding goes at various parts of this, there are two possible answers that I'll consider correct. Just put Formula of hydrate Analysis of Alum 138 down one of them.) 60