Chemical formula for this hydrate Using the chemical formula of the hydrate determined above, write the general bal- anced equation for the dehydration reaction Fe - 55.8s

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I am having issues balancing this equation for this chemical formula of a hydrate.
Cl3- XH20.
12.826 g
12.813 g
15.667 g
15.327 g
ible,
14.533 g
14.321 g
1.7074
1.5087
L134 1.006g
40-016%
d39,96lo %
x 100]
39.916%
te
(convert e
Cl3)
1023
4,829y 10?3 le.058y pa
ad (#4 ÷ #3) :1 ib671
s compound
arest integer
-613
.0657 1
te determined above, write the general bal-
ion
Transcribed Image Text:Cl3- XH20. 12.826 g 12.813 g 15.667 g 15.327 g ible, 14.533 g 14.321 g 1.7074 1.5087 L134 1.006g 40-016% d39,96lo % x 100] 39.916% te (convert e Cl3) 1023 4,829y 10?3 le.058y pa ad (#4 ÷ #3) :1 ib671 s compound arest integer -613 .0657 1 te determined above, write the general bal- ion
PRE-LAB ASSIGNMENT IEXPERIMENT B: MOLAR RATIOS
6.
Determine the formula for the unkpown hydrate below from the experimental data given.
Formula of Hydrate that you used is FeClg xH,0.
12.813 g
Mass of crucible and cover
12.826 g
a.
15.327 g
b. Mass of crucible, cover, and hydrate
c. Mass of hydrate (b-a)
d. Mass of anhydrous compound, crucible,
and cover after heating
15.667 g
2.8419
25149
14.533 g
14.321 g
1.508
Mass of anhydrous compound (d – a)
f. Mass of water lost (c – e)
1.7074
L.1342
e.
SUMMARY OF CALCULATIONS
40-016%
39.9166 %
1. Percent by mass water in hydrate [(f ÷ c) x 100]
39.916%
2. Average percent by mass water in hydrate
3. Moles of anhydrous compound remaining (convert e
in grams to moles using molar mass of FeCl3)
4. Moles of water lost (convert f in grams to
moles using molar mass of water)
5. Molar ratio of water: anhydrous compound (#4 ÷ #3) -blos
6. Average molar ratio of water to anhydrous compound
4.829y 1023 l6.058y pr
:1 1,71
-6657
:1
:1
7. Average ratio (value in #5) rounded to nearest integer
:1
8. Chemical formula for this hydrate
9. Using the chemical formula of the hydrate determined above, write the general bal-
anced equation for the dehydration reaction
Fe = 55.85
Cl (35.45)3
to bsotan
Fe Cl3 t
H2 O
Fell) + Cly
Fe Cla + H20 >
Transcribed Image Text:PRE-LAB ASSIGNMENT IEXPERIMENT B: MOLAR RATIOS 6. Determine the formula for the unkpown hydrate below from the experimental data given. Formula of Hydrate that you used is FeClg xH,0. 12.813 g Mass of crucible and cover 12.826 g a. 15.327 g b. Mass of crucible, cover, and hydrate c. Mass of hydrate (b-a) d. Mass of anhydrous compound, crucible, and cover after heating 15.667 g 2.8419 25149 14.533 g 14.321 g 1.508 Mass of anhydrous compound (d – a) f. Mass of water lost (c – e) 1.7074 L.1342 e. SUMMARY OF CALCULATIONS 40-016% 39.9166 % 1. Percent by mass water in hydrate [(f ÷ c) x 100] 39.916% 2. Average percent by mass water in hydrate 3. Moles of anhydrous compound remaining (convert e in grams to moles using molar mass of FeCl3) 4. Moles of water lost (convert f in grams to moles using molar mass of water) 5. Molar ratio of water: anhydrous compound (#4 ÷ #3) -blos 6. Average molar ratio of water to anhydrous compound 4.829y 1023 l6.058y pr :1 1,71 -6657 :1 :1 7. Average ratio (value in #5) rounded to nearest integer :1 8. Chemical formula for this hydrate 9. Using the chemical formula of the hydrate determined above, write the general bal- anced equation for the dehydration reaction Fe = 55.85 Cl (35.45)3 to bsotan Fe Cl3 t H2 O Fell) + Cly Fe Cla + H20 >
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