If you have 35.67g of Copper (II) Sulfate how many grams of just copper are present?Convert 35.67g of Copper (II) Sulfate into mols .Convert 35.67g of Copper (II) Sulfate into molecules of Copper (II) Sulfate.

Answered: If you have 35.67g of Copper (II)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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If you have 35.67g of Copper (II) Sulfate how many grams of just copper are present?
Convert 35.67g of Copper (II) Sulfate into mols .
Convert 35.67g of Copper (II) Sulfate into molecules of Copper (II) Sulfate.

Expert Solution

Step 1: Determination of number of grams of Copper present in 35.67 g of CuSO4.

Mass of Copper(II) sulfate = 35.67 grams

For determination of number of grams of Copper present in 35.67 g of Copper(II) sulfate we determine the molar mass of Copper(II) sulfate .

The molecular formula of Copper(II) sulfate is CuSO₄.

Molar mass of CuSO₄ is :

$C u S O_{4} = (1 \times A t o m i c m a s s o f C u) + (1 \times A t o m i c m a s s o f S) + (4 \times A t o m i c m a s s o f O) C u S O_{4} = (1 \times 63.546 g) + (1 \times 32.065 g) + (4 \times 15.999 g) C u S O_{4} = 63.546 g + 32.065 g + 63.996 g C u S O_{4} = 159.607 g$

Therefore molar mass of CuSO₄ is 159.607 grams.

There is one Cu atom present in CuSO₄. So, if 159.607 grams of CuSO₄ contains 63.546 grams of Copper then 35.67 grams of CuSO₄ will contain is given by:

$159.607 g o f C u S O_{4} c o n t a i n s \to 63.546 g r a m s o f C o p p e r ⤨ 35.67 g o f C u S O_{4} c o n t a i n s \to x x = \frac{63.546 g r a m s o f C o p p e r \times 35.67 g o f C u S O_{4} c o n t a i n s}{159.607 g o f C u S O_{4} c o n t a i n s} x = 14.20 g o f C u S O_{4}$

Therefore, 35.67 g of CuSO₄ contains 14.20 grams of Copper.

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