How many mL of 0.759 M HCl are needed to dissolve 7.70 g of CaCO2?2HCI(aq) + CaC03(s)CaCl2(aq) + H2O(1) + CO2(g)mL

Answered: How many mL of 0.759 M HCl are needed…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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How many mL of 0.759 M HCl are needed to dissolve 7.70 g of CaCO2?
2HCI(aq) + CaC03(s)
CaCl2(aq) + H2O(1) + CO2(g)
mL

Expert Solution

Step 1

The first part of this is answer is to use stoichiometry to convert grams of CaCO₃ to mol HCl.

Once we know mol of HCl, you can then calculate the volume using the given molarity of HCl.

The stoichiometry process is as follows:

g CaCO₃ --> mol CaCO₃ --> mol HCl

Step 1. Convert g CaCO₃ to mol CaCO₃ using the molar mass of CaCO₃ = 100 g/mol

7.70g CaCO₃ x 1 mol CaCO₃ / 100 g CaCO₃ = 0.077 mol CaCO₃

Step 2. Convert mol CaCO₃ to mol HCl using the mole ratio from the balanced chemical reaction. From the reaction you can see that for every 1 mole of CaCO₃ that reacts, you need 2 moles of HCl.

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