How many grams of N2 are needed to make 444 g of NBr3 ? N2 + 3 Br2 → 2 NBr3 + 44.0 kJ The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g
How many grams of N2 are needed to make 444 g of NBr3 ?
N2 + 3 Br2 → 2 NBr3 + 44.0 kJ
The molar mass of NBr3 is 253.719 g and the molar mass of N2 is 28.013 g
_______________ mol NBr3
(444 g NBr3)(–––––––––––––––––––––––––) = ______________ mol NBr3
____________________ g NBr3
_______________ mol N2
_______________ mol NBr3 (–––––––––––––––––––––––––) = ___________---- mol N2
_________________ mol NBr3
_______________ g N2
_____________________ mol N2 (–––––––––––––––––––––––––) = ___________________ g N2
__________________ mol N2
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