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The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done this!). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) --> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 How much hydrochloric acid, in g, would I need to use if I wanted to make 85.0 L of hydrogen gas?

The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done this!). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) --> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 How much hydrochloric acid, in g, would I need to use if I wanted to make 85.0 L of hydrogen gas?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 How much hydrochloric acid, in g. would I need to use if I wanted to make 85.0 L of hydrogen gas?
Transcribed Image Text:The balanced equation below shows a simple way of manufacturing hydrogen gas in lab (you've done thisl). For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 Al(s) + 6 HCI(aq) -> 2 AICI3(aq) + 3 H2(g) 26.982 36.461 133.341 2.016 How much hydrochloric acid, in g. would I need to use if I wanted to make 85.0 L of hydrogen gas?
The balanced equation for the combustion of butane, CAH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 C4H10(g) + 13 02(g) -> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 How many mL of carbon dioxide gas will be produced by the combustion of 45.0 mg of butane?
Transcribed Image Text:The balanced equation for the combustion of butane, CAH10, is shown below. For your convenience, the molar mass of each substance is shown below their formulas (in purple). Use this information to make the requested calculation: 2 C4H10(g) + 13 02(g) -> 8 CO2(g) + 10 H20(1) 58.124 32 44.011 18.016 How many mL of carbon dioxide gas will be produced by the combustion of 45.0 mg of butane?
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