■O* No, the concentration HCl has been calculated incorrectly.The expression you should be evaluating is:Mícı(mmol mL¯¹)Where:=●MNaOH (Avg)(mmolmL-1) × VNaOH(mL)VHCI (ML)MNaOH (Avg) is average molarity of NaOH• VN₂OH is the volume of NaOHVÍCI is the volume of HCISOLVE1 mmol HCl1 mmol NaOHAt least 6 significant figures should be retained to prevent accumulating rounding errors when the value is used in asubsequent calculation. Please complete the following table. For each of your acceptable trials, enter the volume of HCl solution used (mL), the correspondingvolume of NaOH (mL) required to reach the endpoint, and the calculated molarity of your HCl solution. Use the average molarity ofyour NaOH solution in your calculations.Trial123Vol of HCl solution(mL)5.545.255.25Vol of NaOH solution(mL)25.0025.0025.00Avg. M ofNaOH(from part 1)0.0900235M HCl (M)Unrounded0 A33RoundedPa333

Sodium hydroxide reacts with hydrochloric acid, to form sodium chloride and water. The equation for…

Please complete the following table. For each of your acceptable trials, enter the volume of HCl solution used (mL), the corresponding volume of NaOH (mL) required to reach the endpoint, and the calculated molarity of your HCl solution. Use the average molarity of your NaOH solution in your calculations. Trial 1 2 3 Vol of HCl solution (mL) 5.54 5.25 5.25 Vol of NaOH solution (mL) 25.00 25.00 25.00 Avg. M of NaOH (from part 1) 0.0900235 M HCl (M) Unrounded 0 3 3 Rounded D 3 3 3

Please complete the following table. For each of your acceptable trials, enter the volume of HCl solution used (mL), the corresponding volume of NaOH (mL) required to reach the endpoint, and the calculated molarity of your HCl solution. Use the average molarity of your NaOH solution in your calculations. Trial 1 2 3 Vol of HCl solution (mL) 5.54 5.25 5.25 Vol of NaOH solution (mL) 25.00 25.00 25.00 Avg. M of NaOH (from part 1) 0.0900235 M HCl (M) Unrounded 0 3 3 Rounded D 3 3 3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

■O
* No, the concentration HCl has been calculated incorrectly.
The expression you should be evaluating is:
Mícı(mmol mL¯¹)
Where:
=
●
MNaOH (Avg)(mmolmL-1) × VNaOH(mL)
VHCI (ML)
MNaOH (Avg) is average molarity of NaOH
• VN₂OH is the volume of NaOH
VÍCI is the volume of HCI
SOLVE
1 mmol HCl
1 mmol NaOH
At least 6 significant figures should be retained to prevent accumulating rounding errors when the value is used in a
subsequent calculation.

Please complete the following table. For each of your acceptable trials, enter the volume of HCl solution used (mL), the corresponding
volume of NaOH (mL) required to reach the endpoint, and the calculated molarity of your HCl solution. Use the average molarity of
your NaOH solution in your calculations.
Trial
1
2
3
Vol of HCl solution
(mL)
5.54
5.25
5.25
Vol of NaOH solution
(mL)
25.00
25.00
25.00
Avg. M of
NaOH
(from part 1)
0.0900235
M HCl (M)
Unrounded
0 A
3
3
Rounded
P
a
3
3
3

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Step 1: Acid base titration

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Step 2: Concentration of HCl for the first trial

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Step 3: Concentration of HCl for the second and third trials

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