Answered: 3 CuO(s) + 2 Al(s) → 3 Cu(s) + Al2O3(s)…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3 CuO_(s) + 2 Al_(s) → 3 Cu_(s) + Al₂O_3(s)

25.0 g of copper(II) oxide are combined with 25.0 g of Al , and the mixture is heated strongly to react.

molar masses (g/mol): CuO - 79.55 Al - 26.98 Cu - 63.55

If 18.2 g of Cu metal is recovered from the reaction, what is the percent yield of the reaction?

Do not include the percent sign (%) on your submitted answer.

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$Recall the given reaction, 3 CuO (s) + 2 Al (s) \to 3 Cu (s) + {Al}_{2} O_{3} (s) 25.0 g of copper (II) oxide are combined with 25.0 g of Al, 18.2 g of Cu metal is recovered from the reaction . We have to calculate the percent yield of the reaction .$

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