How many grams of Mg3(PO4)2 are in 10.00 mL of a 2.500 M solution ? The GFW for magnesium phosphate is 262.87 g. (10.00 mL)(- %3D mL mol g L)(- -) = mol (- %3D L mol а. 3.000 b. 2.500 C. 10.00 d. 1.000 е. 2.000 f. 9.000 g. 6.000 h. 8.000 i. 0.02500 j. 47.00 k. 5.00 I. 50.00 m. 25.0 n. 0.02041 o. 97.98 р. 30.62 q. 6.572 r. 0.6124 S. 262.87 t. 0.1800 u. 3.000 x 103 V. 7.500 w. 0.6667 х. О.200 у. 2.67 z. 2.67 x 103 аа. 103 bb. сс. 30.62 dd. 1971 ee. 0.01000
How many grams of Mg3(PO4)2 are in 10.00 mL of a 2.500 M solution ? The GFW for magnesium phosphate is 262.87 g. (10.00 mL)(- %3D mL mol g L)(- -) = mol (- %3D L mol а. 3.000 b. 2.500 C. 10.00 d. 1.000 е. 2.000 f. 9.000 g. 6.000 h. 8.000 i. 0.02500 j. 47.00 k. 5.00 I. 50.00 m. 25.0 n. 0.02041 o. 97.98 р. 30.62 q. 6.572 r. 0.6124 S. 262.87 t. 0.1800 u. 3.000 x 103 V. 7.500 w. 0.6667 х. О.200 у. 2.67 z. 2.67 x 103 аа. 103 bb. сс. 30.62 dd. 1971 ee. 0.01000
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Educational Website: Calculation of Mass of Mg₃(PO₄)₂ in Solution**
**Problem Statement:**
How many grams of Mg₃(PO₄)₂ are in 10.00 mL of a 2.500 M solution? The gram formula weight (GFW) for magnesium phosphate is 262.87 g.
**Calculation Steps:**
1. **Convert Volume to Liters:**
\[
\text{Volume in Liters} = (\text{10.00 mL}) \left( \frac{1 \text{ L}}{1000 \text{ mL}} \right) = \underline{\hspace{1cm}} \text{ L}
\]
2. **Calculate Moles of Solution:**
\[
\text{Moles} = (\text{Volume in Liters}) \times (2.500 \text{ M}) = \underline{\hspace{1cm}} \text{ mol}
\]
3. **Convert Moles to Grams:**
\[
\text{Grams} = (\text{Moles}) \left( \frac{262.87 \text{ g}}{1 \text{ mol}} \right) = \underline{\hspace{1cm}} \text{ g}
\]
**Choices for Fill-in-the-Blanks:**
a. 3.000
b. 2.500
c. 10.00
d. 1.000
e. 2.000
f. 9.000
g. 6.000
h. 8.000
i. 0.02500
j. 47.00
k. 5.00
l. 50.00
m. 25.0
n. 0.02041
o. 0.97
p. 30.62
q. 6.572
r. 0.6124
s. 262.87
t. 0.1800
u. 3.000 x 10³
v. 7.500
w. 0.6667
x. 0.200
y. 2.67
z. 2.67 x 10³
aa. 10³
bb. cc. 30.62](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F674b5627-6eeb-4539-9ecd-a1ecdabb7121%2F77dab439-8a41-4b17-a843-ee2f4257d57f%2Fobskbbf_processed.png&w=3840&q=75)
Transcribed Image Text:**Educational Website: Calculation of Mass of Mg₃(PO₄)₂ in Solution**
**Problem Statement:**
How many grams of Mg₃(PO₄)₂ are in 10.00 mL of a 2.500 M solution? The gram formula weight (GFW) for magnesium phosphate is 262.87 g.
**Calculation Steps:**
1. **Convert Volume to Liters:**
\[
\text{Volume in Liters} = (\text{10.00 mL}) \left( \frac{1 \text{ L}}{1000 \text{ mL}} \right) = \underline{\hspace{1cm}} \text{ L}
\]
2. **Calculate Moles of Solution:**
\[
\text{Moles} = (\text{Volume in Liters}) \times (2.500 \text{ M}) = \underline{\hspace{1cm}} \text{ mol}
\]
3. **Convert Moles to Grams:**
\[
\text{Grams} = (\text{Moles}) \left( \frac{262.87 \text{ g}}{1 \text{ mol}} \right) = \underline{\hspace{1cm}} \text{ g}
\]
**Choices for Fill-in-the-Blanks:**
a. 3.000
b. 2.500
c. 10.00
d. 1.000
e. 2.000
f. 9.000
g. 6.000
h. 8.000
i. 0.02500
j. 47.00
k. 5.00
l. 50.00
m. 25.0
n. 0.02041
o. 0.97
p. 30.62
q. 6.572
r. 0.6124
s. 262.87
t. 0.1800
u. 3.000 x 10³
v. 7.500
w. 0.6667
x. 0.200
y. 2.67
z. 2.67 x 10³
aa. 10³
bb. cc. 30.62
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