How many gallons of gasoline must be burned in order to raise the temperature of 10 liters of water from 25o C to 50o C, assuming 50 percent efficiency in converting the heat released into heat in the water? (The heat of combustion of gasoline is 3.4 × 107 cal/gallon.)

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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18. How many gallons of gasoline must be burned in order to raise the temperature of 10 liters of water from 25o C to 50o C, assuming 50 percent efficiency in converting the heat released into heat in the water?

(The heat of combustion of gasoline is 3.4 × 107 cal/gallon.) 

 

v = { (average speed) d = v,t + at? (distance under acceleration)
W %3D mg (Weight) а %3
Fact
(Acceleration) F= Gm,m2
(Gravity Law)
(Kinetic Energy) PE=mgh (Potential Energy)
p = mv
W = F ·d (Work Done) Q= mcAT (Heat Energy) Q=mL (Latent Heat Energy)
effciency =
%3D
work done
energy provided
Transcribed Image Text:v = { (average speed) d = v,t + at? (distance under acceleration) W %3D mg (Weight) а %3 Fact (Acceleration) F= Gm,m2 (Gravity Law) (Kinetic Energy) PE=mgh (Potential Energy) p = mv W = F ·d (Work Done) Q= mcAT (Heat Energy) Q=mL (Latent Heat Energy) effciency = %3D work done energy provided
Expert Solution
Step 1

Calculate the amount of heat to be absorbed by water to raise its temperature from T1=25o C to T2=50o C.

Qw=mwcT=mwcT2-T1=10 L×1000 g1 ×4.184 J/g·°C×50 °C-25 °C=1.046×106 J×1 cal4.184 J=2.5×105 cal

Here,

The mass of water is mw.

The specific heat capacity of water is cw.

The increase in temperature of water is ∆T.

 

 

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