How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C? Use the values found in Table 15 from Appendix C of your text. Table attached.
How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C? Use the values found in Table 15 from Appendix C of your text. Table attached.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Question
How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C? Use the values found in Table 15 from Appendix C of your text.
Table attached.

Transcribed Image Text:Table 15 Heat Constants
Specific Heat
Heat of
cal/g °C
Vaporization
Heat of Fusion
or
Melting
Boiling
kcal/kg °C
cal/g
or
kcal/kg
cal/g
Point
Point
or
or
(°C)
(°C)
Btu/lb °F
J/kg °C
J/kg
kcal/kg
J/kg
Alcohol,
ethyl
Aluminum
1.04 × 105
3.21 × 105
-117
78.5
0.58
2400
24.9
204
8.54 × 105
660
2057
0.22
920
76.8
Brass
840
0.092
390
Сopper
1083
2330
0.092
390
49.0
2.05 x 105
Glass
0.21
880
Ice
0.51
2100
80
3.35 x 105
Iron (steel)
1540
3000
0.115
481
7.89
3.30 × 104
Lead
327
1620
0.031
130
5.86
2.45 x 104
1.18 x 104
Mercury
-38.9
357
0.033
140
2.82
65.0
2.72 x 105
Silver
961
1950
0.056
230
26.0
1.09 × 105
Steam
0.48
2000
Water
100
80
3.35 × 105
540
2.26 x 106
(liquid)
Zinc
1.00
4190
419
907
0.092
390
23.0
9.63 × 104
Expert Solution

Step 1
Given data:
Mass (m) = 208.6 g
Initial temperature (T0) = -46.1°C
Final temperature (T) = -21°C
Specific heat capacity of ice (c) = 0.51 cal/g°C
Required:
Heat needed to raise the temperature
Step by step
Solved in 2 steps

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