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How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C?  Use the values found in Table 15 from Appendix C of your text. Table attached.

How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C?  Use the values found in Table 15 from Appendix C of your text. Table attached.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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How many calories of heat does it take to change the temperature of 208.6 g of ice from -46.1°C to -21°C?  Use the values found in Table 15 from Appendix C of your text.

Table attached.

Table 15 Heat Constants Specific Heat Heat of cal/g °C Vaporization Heat of Fusion or Melting Boiling kcal/kg °C cal/g or kcal/kg cal/g Point Point or or (°C) (°C) Btu/lb °F J/kg °C J/kg kcal/kg J/kg Alcohol, ethyl Aluminum 1.04 × 105 3.21 × 105 -117 78.5 0.58 2400 24.9 204 8.54 × 105 660 2057 0.22 920 76.8 Brass 840 0.092 390 Сopper 1083 2330 0.092 390 49.0 2.05 x 105 Glass 0.21 880 Ice 0.51 2100 80 3.35 x 105 Iron (steel) 1540 3000 0.115 481 7.89 3.30 × 104 Lead 327 1620 0.031 130 5.86 2.45 x 104 1.18 x 104 Mercury -38.9 357 0.033 140 2.82 65.0 2.72 x 105 Silver 961 1950 0.056 230 26.0 1.09 × 105 Steam 0.48 2000 Water 100 80 3.35 × 105 540 2.26 x 106 (liquid) Zinc 1.00 4190 419 907 0.092 390 23.0 9.63 × 104
Transcribed Image Text:Table 15 Heat Constants Specific Heat Heat of cal/g °C Vaporization Heat of Fusion or Melting Boiling kcal/kg °C cal/g or kcal/kg cal/g Point Point or or (°C) (°C) Btu/lb °F J/kg °C J/kg kcal/kg J/kg Alcohol, ethyl Aluminum 1.04 × 105 3.21 × 105 -117 78.5 0.58 2400 24.9 204 8.54 × 105 660 2057 0.22 920 76.8 Brass 840 0.092 390 Сopper 1083 2330 0.092 390 49.0 2.05 x 105 Glass 0.21 880 Ice 0.51 2100 80 3.35 x 105 Iron (steel) 1540 3000 0.115 481 7.89 3.30 × 104 Lead 327 1620 0.031 130 5.86 2.45 x 104 1.18 x 104 Mercury -38.9 357 0.033 140 2.82 65.0 2.72 x 105 Silver 961 1950 0.056 230 26.0 1.09 × 105 Steam 0.48 2000 Water 100 80 3.35 × 105 540 2.26 x 106 (liquid) Zinc 1.00 4190 419 907 0.092 390 23.0 9.63 × 104
Expert Solution
Step 1

Given data:

Mass (m) = 208.6 g

Initial temperature (T0) = -46.1°C

Final temperature (T) = -21°C

Specific heat capacity of ice (c) = 0.51 cal/g°C

Required:

Heat needed to raise the temperature

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