Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
How does the 10.9 M^-1 turn into 0.0940 M?
![+ kt
[N2O],
t = 1250 seconds
%3D
%3D
20], = 0.108 M
k = 1.10×10-3 M-'s
%3D
1
+ (1.10×10-3 M's)(1250 s
1
%3D
N20],
0.108 M
1
10.6 M-1
%3D
[N2O],
[N2O],
0.0940 M
Use Integrated Rate Law to Calculate Reactant
Concentration at Time t
sition of nitrous oxide at 565 °C
N2(g) + 2 O2(g)
er in N20 with a rate constant of 1.10 x 10-3 M-1s1.
ent is performed where the initial concentration of
M, what is the N,0 concentration after 1250](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e59b0f6-3039-46d3-a26b-d87030adb520%2F58eec14b-84dd-4d7b-a0c1-27f1185ccd4e%2F6g8vhy4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:+ kt
[N2O],
t = 1250 seconds
%3D
%3D
20], = 0.108 M
k = 1.10×10-3 M-'s
%3D
1
+ (1.10×10-3 M's)(1250 s
1
%3D
N20],
0.108 M
1
10.6 M-1
%3D
[N2O],
[N2O],
0.0940 M
Use Integrated Rate Law to Calculate Reactant
Concentration at Time t
sition of nitrous oxide at 565 °C
N2(g) + 2 O2(g)
er in N20 with a rate constant of 1.10 x 10-3 M-1s1.
ent is performed where the initial concentration of
M, what is the N,0 concentration after 1250
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