A tank originally contains 500 L of water with a salt concentration of 2 grams per liter. Water with a concentration of 1 gram/liter is then poured into the tank at a rate of 3 L/min and the well stirred mixture is allowed to flow out of the tank at the same rate. a) Find a formula for Q(t), the quantity of salt in the tank after t minutes. b) Find the limiting quantity of salt in the tank as t → ∞

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A tank originally contains 500 L of water with a salt concentration of 2 grams per liter.
Water with a concentration of 1 gram/liter is then poured into the tank at a rate of
3 L/min and the well stirred mixture is allowed to flow out of the tank at the same rate.
a) Find a formula for Q(t), the quantity of salt in the tank after t minutes.
b) Find the limiting quantity of salt in the tank as t → co
Transcribed Image Text:A tank originally contains 500 L of water with a salt concentration of 2 grams per liter. Water with a concentration of 1 gram/liter is then poured into the tank at a rate of 3 L/min and the well stirred mixture is allowed to flow out of the tank at the same rate. a) Find a formula for Q(t), the quantity of salt in the tank after t minutes. b) Find the limiting quantity of salt in the tank as t → co
Expert Solution
Step 1

the rate of change of a quantity over time. In this case, the quantity being described is the amount of salt in the tank, and the rate of change is described by the differential equation: 

dQ/dt = 3 * (2 - 1) = 3 

where dQ/dt represents the rate of change of the quantity of salt in the tank, 2 - 1 = 1 represents the difference in the concentration of salt between the water that is flowing out and the water that is being added, and 3 represents the rate at which the water is being added and flowing out. The solution to this differential equation,

Q(t) = Q(0) + 3t

This gives us the formula for the quantity of salt in the tank after t minutes.

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