How do you find the value of a resistance R1, in a circuit when the equivalent resistance is 40 ohms, given that: R2 = 12 ohm in series with R3 = 40 ohms whom combined are in parallel with R4 = 20 ohms, all in parallel to R1. And to find the current in each resistor, do I just apply the equation, I = V/R, given that the circuit runs on an 28 volt batt.

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A: The values of currents are as follows,I1 = 0.485900217amps,I2 = -0.5075922 amps,I3 = 0.993492417…

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Q: R, = 8 kN R, = 8 kN V, = 2.8 V V, = 2.5 V V, = 2.8 V V, = 2.5 V R, = 4 kN R, = 4 kN R, = 4 kN R, = 4…

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A: Given ,V=12 voltR1=5 MΩRab=10 MΩUsing voltage divider rule at Rab, Vab=12 Volt×10 MΩ10 MΩ+5 MΩ= 8…