The "lead" in your pencil is actually graphite, a form of carbon. If the 0.7mm diameter "lead" was actually made out of uranium and was 4.1 cm long, what would be it's resistance in Q at 98 degrees C? (uranium resistivity p = 2.8 x 10^-7 Qm at 20 C and a = -2.61 x 10^-3 C^-1)
The "lead" in your pencil is actually graphite, a form of carbon. If the 0.7mm diameter "lead" was actually made out of uranium and was 4.1 cm long, what would be it's resistance in Q at 98 degrees C? (uranium resistivity p = 2.8 x 10^-7 Qm at 20 C and a = -2.61 x 10^-3 C^-1)
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![The "lead" in your pencil is actually graphite, a form of carbon. If the 0.7mm diameter "lead" was
actually made out of uranium and was 4.1 cm long, what would be it's resistance in 2 at 98 degrees
C?
(uranium resistivity p = 2.8 x 10^-7 Qm at 20 C and a = -2.61 x 10^-3 C^-1)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F74be4292-7d75-4748-a8da-51953667dfbc%2F6962ac6d-342e-45a1-80d3-ba61cd81f7b6%2Fqfw952_processed.png&w=3840&q=75)
Transcribed Image Text:The "lead" in your pencil is actually graphite, a form of carbon. If the 0.7mm diameter "lead" was
actually made out of uranium and was 4.1 cm long, what would be it's resistance in 2 at 98 degrees
C?
(uranium resistivity p = 2.8 x 10^-7 Qm at 20 C and a = -2.61 x 10^-3 C^-1)
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