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How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as: P=emf^2(R/(R+r)^2

How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as: P=emf^2(R/(R+r)^2

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Context: Source of EMF and RC Circuits                                                                                                                                                                             
How do you derive Equation 4 from Equations 1 and 3? Equation 1 is Current, I= emf/(R+r) and Equation 3 is power, P= IV= I^2R . Equation 4 is Making use of Eq. (1) in Eq. (3), one can show that power, P, supplied by the battery to the resistive load, R, can be written as:   P=emf^2(R/(R+r)^2 

The formula shown is: \[ P = \mathcal{E}^2 \frac{R}{(R + r)^2} \] This equation represents a mathematical relationship where: - \( P \) is the power. - \( \mathcal{E} \) is a variable which represents electromotive force (emf). - \( R \) stands for resistance. - \( r \) indicates internal resistance. This formula is often used in the context of electrical circuits to calculate the power delivered to a load resistance \( R \) when considering internal resistance \( r \) of a source with electromotive force \( \mathcal{E} \).
Transcribed Image Text:The formula shown is: \[ P = \mathcal{E}^2 \frac{R}{(R + r)^2} \] This equation represents a mathematical relationship where: - \( P \) is the power. - \( \mathcal{E} \) is a variable which represents electromotive force (emf). - \( R \) stands for resistance. - \( r \) indicates internal resistance. This formula is often used in the context of electrical circuits to calculate the power delivered to a load resistance \( R \) when considering internal resistance \( r \) of a source with electromotive force \( \mathcal{E} \).
The equation displayed in the image is: \[ I = \frac{\mathcal{E}}{(R + r)} \] This is equation (1). Explanation: - \( I \) represents the current. - \( \mathcal{E} \) represents the electromotive force (emf). - \( R \) is the external resistance. - \( r \) is the internal resistance. This equation is often used in physics to describe the current flowing through a circuit with both internal and external resistances.
Transcribed Image Text:The equation displayed in the image is: \[ I = \frac{\mathcal{E}}{(R + r)} \] This is equation (1). Explanation: - \( I \) represents the current. - \( \mathcal{E} \) represents the electromotive force (emf). - \( R \) is the external resistance. - \( r \) is the internal resistance. This equation is often used in physics to describe the current flowing through a circuit with both internal and external resistances.
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