how do we know which one is carbon 1 ，which one is carbon2？Did I draw the compound correctly？Step by step explain why I know that The stereochemistry of carbon‑1 is S. （but how do you know which one is carbon 1？？？？）The other bromine is attached to carbon‑2？does Br has priority in naming？if so ，dash Br and wedge Br ，which one get priority？why tert tert-butyl-group can’t be Carbon 1 or carbon 2？The tert‑butyl group is attached to carbon‑4 （base on the picture，why not carbon 3 or carbon 5？？？ **Interactive 3D Molecular Structure**Explore the 3D molecular structure by clicking and dragging to rotate it, or use the control options on the right to manipulate the view. The molecule is represented with different colored spheres, each indicating a specific type of atom:- **Carbon (C):** Black spheres- **Hydrogen (H):** White spheres- **Bromine (Br):** Red spheres### Controls:- **Rotate X:** Adjust the molecule's orientation around the X-axis.- **Rotate Y:** Adjust the molecule's orientation around the Y-axis.- **Rotate Z:** Adjust the molecule's orientation around the Z-axis.- **Zoom In/Out:** Enlarge or reduce the view of the molecule.- **Label Atoms:** Display or hide atom labels on the molecular structure.This interactive model helps visualize the spatial arrangement and bonding of atoms in the molecule. The image features a hand-drawn chemical structure of a cyclohexane ring, which is a six-membered carbon ring. Attached to the ring are two bromine (Br) atoms. The bromine groups are attached to the ring at different positions, indicating a specific stereochemistry.The drawing uses wedge and dash bonds:- The wedge bond (bold triangular line) represents a bond coming out of the plane towards the viewer.- The dashed line indicates a bond going into the plane away from the viewer.This suggests that the bromine atoms are in a trans configuration, as they are on opposite sides of the cyclohexane ring. This diagram is often used in organic chemistry to depict molecules with specific 3D structures, which can be crucial for understanding their chemical behavior and interactions.

According to IUPAC namenclature whenever the more than one substituents are attached the namng order based on the alphabetical order. That is if there are two groups are attached then first priority given to that substituents which alphabet comes first than the other alphabet. For example, if methyl and ethyl groups are present then ethyl group gets higher priority than methyl because alphabet letter 'e' comes first than 'm' of the methyl. The structure and name of the compound is In this molecule two groups are present i.e. two bromo and one tert-butyl-group i.e. bromine and tert-butyl-group are in competation. So, the alphabet 'B' comes first than alphabet ' T'. So, the first naming priority given to bromo group. According to IUPAC namenclature the number starts in such a way that the substituents gets the lower number. Based on that the numbering starts form the carbon attached to the broken wedged bromine. So, it gets the lower number to second bromine as well as isopropyl group. Therefore, at carbon-1 the bromine below plane and carbon-2 bromine is above the plane and at carbon-4 there is tert-butyl-group. The configuration of chiral carbon-1 is S because according to R/S configuration the priority given based atomic number on the directly attached atoms. That is higher the atomic number it gives the priority 1 . Based, on R/S nomenclature we have to assgn the configuration at C-1. The bromine has atomic number is higher compared to other atoms so it gets priority 1. The second priority given to carbon which is attached to the bromine. The third priority given to -CH2- group. The fourth priority given to hydrogen which is above the plane. After giving the priority the priority direction is clockwise so the configuration is R but the lowest priority is above the plane so we take reverse confuguration S. According to R/S nomenclature always keep lowest priority below the plane.