Complete the table with respect to each structure. m Structure Planar? Completely Conjugated? # of Cyclic pi- electrons? Aromatic, Anti-Aromatic or Non- Aromatic?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Complete the table with respect to each structure. mo ob
Structure
Planar?
Completely
Conjugated?
# of Cyclic pi-
electrons?
Aromatic,
Anti-Aromatic
or Non-
Aromatic?
CH CH CHT
Transcribed Image Text:Complete the table with respect to each structure. mo ob Structure Planar? Completely Conjugated? # of Cyclic pi- electrons? Aromatic, Anti-Aromatic or Non- Aromatic? CH CH CHT
Expert Solution
Step 1
  • Planarity:

In the first structure there is a carbanion present. The hybridization involved in carbanion is sp3. This will not have a planar structure.

In second structure there is 1 Oxygen atom present. Here, O atom is having sp3 hybridization. So, this will not have a planar structure. 

  • Completely conjugated:

First structure is completely conjugated where as second structure is not.

 Chemistry homework question answer, step 1, image 1

  • Cyclic pi electrons :

In 1st structure there are 14 cyclic pi electrons are present.

In 2nd structure there are 10 cyclic pi electrons present.

  • Aromaticity :

1 st structure follows:

(4n+2) pi electron rule where n is equal to 3. (4x3 +2) = 14 pi electrons.

Cyclic conjugated system.

Due to symmetry factor it is aromatic.

So it is aromatic.

2 nd structure is not a planar structure as it is having a sphybridized Oxygen atom.

Cyclic Conjugation is not complete.

Does not follow Huckel's rule.

So it is non-aromatic.

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