How did you get this. Can you show your solution and explain how it become like this?
How did you get this. Can you show your solution and explain how it become like this?
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How did you get this. Can you show your solution and explain how it become like this?
![Karr
Step2
b)
le
For the population to
the
long
term. We
ensure
within the
stable
50,
50,
= 9000-m +0.00006 (1000 + m) (9000 m)
= 9000 -mv + 6×10-5 (9x 106 + 8000m - m²)
= 9540 - (1 - 48) m
-m
= 9540 -
0 ≤ 9540 -
O
for
6
10⁰ < 100m².
the
the
The
expression
gives positive vahre
to
that
we
Кли
Hence
52
108
long
m
< 100m², 52m +
weed
52
021
m
+52m - 0.954X106 <0.
46000 < 106.
2
survive in
weed to
100m²
⇒ 100m² +52 m -
954000 ≤0
⇒ (m-97.4) (m + 97.9) 10.
97.9
and
tb> m 30
an+1
range.
mm² < 10000
100m² +52m + 46000 always.
for myo.
find the range of m
+52m + 46000 ≤106
falls
is 97,
maximum value of
population
form
m ≤ 97.4.
m
survives in
for which
the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F000f2982-3c3c-4d1b-a74e-b4b6d47726ea%2F03ef5f2d-081b-43af-b513-485635c14ed0%2Fzkpmwqs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Karr
Step2
b)
le
For the population to
the
long
term. We
ensure
within the
stable
50,
50,
= 9000-m +0.00006 (1000 + m) (9000 m)
= 9000 -mv + 6×10-5 (9x 106 + 8000m - m²)
= 9540 - (1 - 48) m
-m
= 9540 -
0 ≤ 9540 -
O
for
6
10⁰ < 100m².
the
the
The
expression
gives positive vahre
to
that
we
Кли
Hence
52
108
long
m
< 100m², 52m +
weed
52
021
m
+52m - 0.954X106 <0.
46000 < 106.
2
survive in
weed to
100m²
⇒ 100m² +52 m -
954000 ≤0
⇒ (m-97.4) (m + 97.9) 10.
97.9
and
tb> m 30
an+1
range.
mm² < 10000
100m² +52m + 46000 always.
for myo.
find the range of m
+52m + 46000 ≤106
falls
is 97,
maximum value of
population
form
m ≤ 97.4.
m
survives in
for which
the
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