How did you get this. Can you show your solution and explain how it become like this?

icon
Related questions
Question
How did you get this. Can you show your solution and explain how it become like this?
Karr
Step2
b)
le
For the population to
the
long
term. We
ensure
within the
stable
50,
50,
= 9000-m +0.00006 (1000 + m) (9000 m)
= 9000 -mv + 6×10-5 (9x 106 + 8000m - m²)
= 9540 - (1 - 48) m
-m
= 9540 -
0 ≤ 9540 -
O
for
6
10⁰ < 100m².
the
the
The
expression
gives positive vahre
to
that
we
Кли
Hence
52
108
long
m
< 100m², 52m +
weed
52
021
m
+52m - 0.954X106 <0.
46000 < 106.
2
survive in
weed to
100m²
⇒ 100m² +52 m -
954000 ≤0
⇒ (m-97.4) (m + 97.9) 10.
97.9
and
tb> m 30
an+1
range.
mm² < 10000
100m² +52m + 46000 always.
for myo.
find the range of m
+52m + 46000 ≤106
falls
is 97,
maximum value of
population
form
m ≤ 97.4.
m
survives in
for which
the
Transcribed Image Text:Karr Step2 b) le For the population to the long term. We ensure within the stable 50, 50, = 9000-m +0.00006 (1000 + m) (9000 m) = 9000 -mv + 6×10-5 (9x 106 + 8000m - m²) = 9540 - (1 - 48) m -m = 9540 - 0 ≤ 9540 - O for 6 10⁰ < 100m². the the The expression gives positive vahre to that we Кли Hence 52 108 long m < 100m², 52m + weed 52 021 m +52m - 0.954X106 <0. 46000 < 106. 2 survive in weed to 100m² ⇒ 100m² +52 m - 954000 ≤0 ⇒ (m-97.4) (m + 97.9) 10. 97.9 and tb> m 30 an+1 range. mm² < 10000 100m² +52m + 46000 always. for myo. find the range of m +52m + 46000 ≤106 falls is 97, maximum value of population form m ≤ 97.4. m survives in for which the
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

Blurred answer