Find the horizontal displacement due to the rotation of the earth if a body dropped from a fixed platform at a height (h) at the equator, neglecting the effects of air resistance. What is the displacement if h=5 km? I would appreciate help with c-g :) **Section b:**Write your available equations (in this case the three components of the Coriolis acceleration \( \frac{du}{dt}, \frac{dv}{dt}, \frac{dw}{dt} \) and the vertical acceleration due to gravity as explained in the notes above):\[\frac{du}{dt} = 2 \Omega v \sin \phi - 2 \Omega w \cos \phi\]\[\frac{dv}{dt} = -2 \Omega u \sin \phi\]\[\frac{dw}{dt} = 2 \Omega u \cos \phi\]**Section c:**Cancel out the unnecessary terms in part b—do it right there (there are no initial horizontal motions) and write down the useful equation. ---d. **Figure out an expression for w in terms of t and g by integrating the vertical acceleration equation** (from zero to w and from zero to t).e. **Substitute w in the Coriolis equation** (leftover in part c).f. **Integrate your equation** (zero to u and zero to t). You should end up with an expression for u as a function of t.g. **But what you need is the displacement x, so you need to change u in terms of x and integrate again** (zero to x and zero to t). You should end up with an expression for x as a function of t. This is not the end of the problem since you don’t have t. All you have is h.--- Note: There are no graphs or diagrams in this text.

Given: h=5 km The objective is to find the horizontal displacement due to the rotation of the earth…

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