(a) Using the average distance of Venus from the Sun and the orbital period of Venus, find the centripetal acceleration (in m/s) of Venus in its motion about the Sun. (Assume the orbit is circular. Enter the magnitude.)m/s?(b) Compare this value to the magnitude of the centripetal acceleration at the equator due to Venus's rotation.dc, Venus about Sunadc, equator CelestialMean DistancePeriod of RevolutionPeriod ofEccentricityof Orbitfrom Sun (millionkm)(d = days) (y = years)ObjectRotation atEquatorSun27 dMercury57.988 d59 d0.206Venus108.2224.7 d243 d0.007Earth149.6365.26 d23 h 56 min 4 s0.017Mars227.9687 d24 h 37 min 23 s0.093Jupiter778.411.9 y9 h 50 min 30 s0.048Saturn1426.729.5 610 h 14 min0.054Uranus2871.084.0 y17 h 14 min0.047Neptune4498.3164.8 y16 h0.009Earth's149.6 (0.386 fromEarth)27.3 d27.3 d0.055МoonEquatorial Diameter(km)CelestialMass (Earth = 1)Density (g/cm³)%3DObjectSun1,392,000333,000.001.4Mercury48790.065.4Venus12,1040.825.2Earth12,7561.005.5Mars67940.113.9Jupiter142,984317.831.3Saturn120,53695.160.7Uranus51,11814.541.3Neptune49,52817.151.6Earth's34760.013.3МoonTable D1 Astronomical DataOther Data:Mass of Earth: 5.97 x 1024 kgMass of the Moon: 7.36 x 1022 kgMass of the Sun: 1.99 x 103° kg

(a) Obtain the following data from the given table: The mean distance of Venus from the sun is d…

(a) Using the average distance of Venus from the Sun and the orbital period of Venus, find the centripetal acceleration (in m/s2) of Venus in its motion about the Sun. (Assume the orbit is circular. Enter the magnitude.) m/s2 (b) Compare this value to the magnitude of the centripetal acceleration at the equator due to Venus's rotation. ac. Venus about Sun ac, equator

(a) Using the average distance of Venus from the Sun and the orbital period of Venus, find the centripetal acceleration (in m/s2) of Venus in its motion about the Sun. (Assume the orbit is circular. Enter the magnitude.) m/s2 (b) Compare this value to the magnitude of the centripetal acceleration at the equator due to Venus's rotation. ac. Venus about Sun ac, equator

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

Question

100%

(a) Using the average distance of Venus from the Sun and the orbital period of Venus, find the centripetal acceleration (in m/s) of Venus in its motion about the Sun. (Assume the orbit is circular. Enter the magnitude.)
m/s?
(b) Compare this value to the magnitude of the centripetal acceleration at the equator due to Venus's rotation.
dc, Venus about Sun
a
dc, equator

Celestial
Mean Distance
Period of Revolution
Period of
Eccentricity
of Orbit
from Sun (million
km)
(d = days) (y = years)
Object
Rotation at
Equator
Sun
27 d
Mercury
57.9
88 d
59 d
0.206
Venus
108.2
224.7 d
243 d
0.007
Earth
149.6
365.26 d
23 h 56 min 4 s
0.017
Mars
227.9
687 d
24 h 37 min 23 s
0.093
Jupiter
778.4
11.9 y
9 h 50 min 30 s
0.048
Saturn
1426.7
29.5 6
10 h 14 min
0.054
Uranus
2871.0
84.0 y
17 h 14 min
0.047
Neptune
4498.3
164.8 y
16 h
0.009
Earth's
149.6 (0.386 from
Earth)
27.3 d
27.3 d
0.055
Мoon
Equatorial Diameter
(km)
Celestial
Mass (Earth = 1)
Density (g/cm³)
%3D
Object
Sun
1,392,000
333,000.00
1.4
Mercury
4879
0.06
5.4
Venus
12,104
0.82
5.2
Earth
12,756
1.00
5.5
Mars
6794
0.11
3.9
Jupiter
142,984
317.83
1.3
Saturn
120,536
95.16
0.7
Uranus
51,118
14.54
1.3
Neptune
49,528
17.15
1.6
Earth's
3476
0.01
3.3
Мoon
Table D1 Astronomical Data
Other Data:
Mass of Earth: 5.97 x 1024 kg
Mass of the Moon: 7.36 x 1022 kg
Mass of the Sun: 1.99 x 103° kg

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