You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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You're designing a highway so that the maximum centripetal acceleration on a curve is no more than 1.7 m/s2. What is the minimum curvature radius to accommodate a 52-km/h maximum speed? Give your answer in meters
I know the formula involves a= v^2/r and we get r by itself; and then, we are to find minimum curvature radius. My question has to do with a conversion of 52 km to meters, and yes, km=1000 m. Can you help me to conceptualize (52 km/h)^2 to (14.4 m/s)^2 better?
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