Horizontal boom OAB with total length 2L = 4 m is held in equlibrium by cables AD and BE and by a ball- and-socket joint at O. A crate with weight W = 725 N is hung from the end of the boom at point B. The coordinates of points D and Eare: . . D = (1, 0, 2) m E = (-2,0, 1.5) m Determine the tension in cables AD and BE and the reaction forces at ball-and-socket joint O. You may neglect the mass of the boom in your analysis. When reporting your answer for the reactions at O, use the following sign convention following the coordinate system in the figure: Ro= (Oz)i + (Oy)j + (O₂)k.

International Edition---engineering Mechanics: Statics, 4th Edition
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Chapter4: Coplanar Equilibrium Analysis
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Horizontal boom OAB with total length 2L = 4 m is held in equlibrium by cables AD and BE and by a ball-
and-socket joint at O. A crate with weight W = 725 N is hung from the end of the boom at point B. The
coordinates of points D and Eare:
D = (1, 0, 2) m
• E=(-2,0,1.5) m
Determine the tension in cables AD and BE and the reaction forces at ball-and-socket joint O. You may
neglect the mass of the boom in your analysis.
When reporting your answer for the reactions at O, use the following sign convention following the coordinate
system in the figure: Řo = (O₂)i + (Oy)j + (O₂)k.
TAD
TEE
Q₂
O₂ =
0,-
>
number (rtol-0.01, atol=1e-05)
number (rtol-0.01, atol-1e-05)
number (rtol=0.01, atol=1e-05)
number (rtol=0.01, atol-1e-05)
number (rtol-0.01, atol=1e-05)
L
NO
NO
NO
N
Ν Θ
AC
y
Transcribed Image Text:Horizontal boom OAB with total length 2L = 4 m is held in equlibrium by cables AD and BE and by a ball- and-socket joint at O. A crate with weight W = 725 N is hung from the end of the boom at point B. The coordinates of points D and Eare: D = (1, 0, 2) m • E=(-2,0,1.5) m Determine the tension in cables AD and BE and the reaction forces at ball-and-socket joint O. You may neglect the mass of the boom in your analysis. When reporting your answer for the reactions at O, use the following sign convention following the coordinate system in the figure: Řo = (O₂)i + (Oy)j + (O₂)k. TAD TEE Q₂ O₂ = 0,- > number (rtol-0.01, atol=1e-05) number (rtol-0.01, atol-1e-05) number (rtol=0.01, atol=1e-05) number (rtol=0.01, atol-1e-05) number (rtol-0.01, atol=1e-05) L NO NO NO N Ν Θ AC y
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