I don't know what I am missing with this problem can you please help me figure out what I am missing in my calculations? The smooth uniform rod AB is supported by aball-and-socket joint at A, the wall at B, and cable BC.The rod has a mass of 11 kg. (Figure 1)Figure1 m.0.5 mCB1.5 m2 m1 of 1Determine the tension in the cable.Express your answer to three significant figures and include theappropriate units.TBC = 50μASubmit Previous Answers Request AnswerPart BNX Incorrect; Try Again; 5 attempts remaining☐☐?Determine the normal reaction at B.Express your answer to three significant figures and include theappropriate units.μA?

Given:The mass of the uniform rod is, .The acceleration due to gravity is, .Tension in cable BC is,…

Answered: The smooth uniform rod AB is supported…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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I don't know what I am missing with this problem can you please help me figure out what I am missing in my calculations?

The smooth uniform rod AB is supported by a
ball-and-socket joint at A, the wall at B, and cable BC.
The rod has a mass of 11 kg. (Figure 1)
Figure
1 m.
0.5 m
C
B
1.5 m
2 m
1 of 1
Determine the tension in the cable.
Express your answer to three significant figures and include the
appropriate units.
TBC = 50
μA
Submit Previous Answers Request Answer
Part B
N
X Incorrect; Try Again; 5 attempts remaining
☐☐
?
Determine the normal reaction at B.
Express your answer to three significant figures and include the
appropriate units.
μA
?

Expert Solution

Step 1: Determine the given data

Given:

The mass of the uniform rod is, $m equals 11 space k g$ .

The acceleration due to gravity is, $g equals 9.81 space m divided by s squared$ .

Tension in cable BC is, $T subscript B C end subscript$ .

y-component of the reaction at A is, $A subscript y$ .

x-component of the reaction at A is, $A subscript z$ .

z-component of the reaction at A is, $A subscript x$ .

The normal reaction at point B is, $R subscript B$ .

The free body diagram of rod is given below,

From the figure take the inclination at point BC we have,

$tan theta equals fraction numerator P e r p e n d i c u l a r over denominator B a s e end fraction tan space theta equals fraction numerator 0.5 space m over denominator 1 space m end fraction theta equals 26.57 degree$

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