Homework Q3: Calculate the standard deviation for the following dataset Laser Power (Watt) Laser Type 0.5-5 He-Ne 8 CO2 3.6 Ruby 0.4-2.5 Ti-Sapphire 10 Er:YAG 25
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- Question 21 Negative values of covariance indicate O a. the standard deviation is negative O b. a negative relation between the x and the y variables c. a negative variance of the y values d. a positive variance of the x valuesThe lengths of pregnancies in a small rural village are normally distributed with a mean of 263 days and a standard deviation of 15 days. In what range would you expect to find the middle 98% of most pregnancies? [Write your answer as a complete sentence] Edit View Insert Format Tools Table B IU A ev T2v レ レ 12pt v Paragraph v 1:13 PM 72°F Sunny 5/7/2022 .. P Type here to search の fo l ins prt sc end 12 delete home f4 f5 & 7 num backspace lock 3 4. 6 8. ... DI 5 %24QUESTION 5 Assume X is normally distributed with a mean of 14.8 and a standard deviation of 4.2. Determine the value for x that solves each of the following. Round the answers to 2 decimal places. a) P(X>x)=D0.05
- Question 4 Use the empirical rule to solve the problem. The amount of Jen's monthly phone bill is normally distributed with a mean of $58 and a standard deviation of $12. What percentage of her phonė bills are between $22 and $94? O 99.99% O 99.7% O 68% O 95% « > A Moving to another question will save this response. 4:42 PM rch 3/25/2021 DII FS PrtScn Home F9 End F10 PgUp PgDn F11 F12 F6 F7 F8 4. 5 6 8. 9. E R T Y U D F G H J K LThe following data consists of birth weights (pounds) of a sample of newborn babies at a local hospital: k 9.3 8.3 9.1 6.9 7.5 7.7 9.2 7.6 6.8 7.4 SUBMIT QUESTION New T *apidNone
- Question 12 Calculate the standard deviation of X. 6 P(X) 0.4 0.6 MacBook Pro 888 #3 $ & 3 4 7 8. E Y U F G J K C V M V エ くO トResearchers at the National Weather Center in Portland, Maine recorded the number of 90° days each year since records were first kept, starting in 1875. The number of 90° days form a normal-shaped distribution, with a mean of μ = 9.6 days and a standard deviation of σ = 1.9. To see if the data showed any evidence of climate change (and specifically global warming), they also computed the mean number of 90° days for the most recent n = 4 years and obtained a mean number of days for the past four years of x̅ = 12.25 days. Using a one-tailed test with α = .05, the researchers completed the calculations, but they need your help in drawing an appropriate conclusion. (According to their calculations, the standard error is sM = 0.95, and the sample mean of x̅ = 12.25 days corresponds to a z-score of z = 2.79.) Using the same one-tailed test (α = .05), determine if the data indicate that the past four years have had significantly more 90° days than would be expected for a random sample from…Question 9 Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 64.7 inches tall. (to 2 decimal places)
- QUESTION 18 Use the following data on distance and interaction frequency: y Interaction frequency x distance Mean 10.3 6.2 Std. dev. What is the standard error of the estimate (i.e., the standard deviation of the residuals)? 4.1 2.8 O 3.052 O 3.214 O 3.117 O 3.250Question 3 Marquis scored 82 in the class with the mean /5.5 and the standard deviation 5.4, but Rhianna scored 69 in the class with the mean 58.9 and the standard deviation 9.1. Who scored relatively better? (Round the answers to 2 decimal places) Marquis's z-score is Marquis's z-score is Select an answer Select an answer less than greater than the same as and Rhianna's z-score is Rhianna's z-score, we conclude that Select an answer Select an answer Rhianna did relatively better Marquis and Rhianna did relatively the same Marquis did relatively better SinceCompute the standard deviation to the nearest 0.01.
