he following data consists of birth weights (pounds) of a sample of newborn babies at local K hospital: 4 7.1 9.3 8.3 9.1 6.9 7.7 9.2 7.6 6.8 7.4 SUBMIT QUESTION 7.5 ↑
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We have given that,
The sample data is,
7.1, 9.3, 8.3, 9.1, 6.9, 7.5, 7.7, 9.2, 7.6, 6.8, 7.4
Then,
We will find the range, variance and standard deviation?
Step by step
Solved in 3 steps with 2 images
- In the US, 43.9% of all people have type O blood, 40.6% have type A blood, 10.8% have type B blood and 4.7% have type AB blood. A researcher wants to see if the distribution of blood type is different for millionaires. The table below shows the results of a random sample of 3488 millionaires. What can be concluded at the a = 0.05 significance level? a. Complete the table by filling in the expected frequencies. Round to the nearest whole number: Frequencies of Blood Type Outcome Frequency Expected Frequency 1521 A 1427 В 376 АВ 164A cereal maker recently sampled 20 of its medium-size oat cereal packages to determine the weights of the cereal in each package. These sample data, measured in ounces, are given below. 14.4 14.9 18.6 14.1 18.9 14.3 15.9 18.5 17.1 18.1 18.7 16.5 17.5 13.1 16.4 15.6 17.3 18.3 13.3 13.2 Calculate the first and third quartiles for these sample data. The first quartile is oz. (Type an integer or decimal rounded to two decimal places as needed.) OZ. The third quartile is (Type an integer or decimal rounded to two decimal places as needed.) OZ.Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.49 0.79 0.72 1.25 0.85 0.84 1.13 0.68 1.43 0.51 1.18 Question content area bottom Part 1 The 5-number summary is enter your response here, enter your response here, enter your response here, enter your response here, and enter your response here, all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)
- 1)Dataset: 88 123 47 45 66 190 157 91 2) Using the dataset from Question #1, what is the median (Round your answer to the one decimal place)?IIT UU I Use the following cell phone airport data speeds (Mbps) from a particular network. Find the percentile corresponding to the data speed 1.4 Mbps. 0.1 0.2 0.2 0.4 0.4 0.4 0.4 0.5 0.5 0.5 O 0.6 0.6 0.7 0.8 0.9 0.9 1.1 1.4 1.4 1.6 1.6 2.1 2.1 2.3 2.3 2.5 2.6 2.7 2.9 3.3 3.8 4.6 4.8 5.9 6.1 6.3 6.9 8.6 9.1 11.2 11.4 11.5 13.3 14.1 14.4 14.5 14.9 15.2 15.4 29.9 Percentile of 1.4 = (Round to the nearest whole number as needed.)Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and ? = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is ? = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. Level of significance = .10 Null and alternate hypotheses. - H0: ? = 4.3 g; H1: ? < 4.3 g; left-tailed Sampling Distribution - The standard normal, since we assume that x has a normal distribution with known ? Compute the z value of the sample test…
- A researcher collected how many grams of fat people on a specific diet consumed at breakfast and at lunch. The data for a sample of 8 people is shown in the table below. xx 11.3 8.2 7.2 3.6 2.3 2.5 2.7 0.4 yy 13.7 10.7 10.2 7.2 6.3 6.5 6.1 4.1 xx = grams of fat in breakfastyy = grams of fat in lunchThis data can be modeled by the equation ˆy=0.84x+4.07.y^=0.84x+4.07.Given this, how many grams of fat in lunch would be expected for a person who consumed 1.2 grams of fat at breakfast? Round to 1 decimal place.Answer =Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and σ = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is μ = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. (a) What is the level of significance? (Enter a number.) State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: μ = 4.3 g; H1: μ > 4.3 g; right-tailed H0: μ < 4.3 g; H1: μ = 4.3 g; left-tailed…the dataset provides information on temperature change in some provinces from china. Analyze it using SPSS and conduct any tests
- A survey was given to 18 employees. One question asked about the one-way distance the employee had to travel for work. The results, in kilometers, are shown below. Kilometers Traveled for Work 12 10 18 3 4 28 5 32 26 10 41 85 1 7 8 5 10 15 Find the first quartile of the data.A lecturer at college wanted to know if he can predict student’s quiz results by asking them tocomplete a simple survey. The result of the survey is given below: Quiz Results EQR Study Hrs Age Sex BBT MB MC AuHS LM 15 10 3 19 0 0 1 1 0 1 14 15 4 24 0 0 1 0 0 1 9 15 1 20 0 10 1 0 0 1 6 10 3 21 0 0 1 1 0 1 14 15 4 21 0 9 1 0 0 1 12 10 6 21 0 2 0 1 0 1 12 13 2 21 1 8 1 0 0 0 15 15 0 20 0 8 1 0 0 1 12 15 3 20 0 10 1 0 0 1 13 15 0.2 19 0 8 1 0 0 1 15 15 2 20 0 6 1 0 1 1 12 14 5 20 0 5 1 1 1 1 14 15 7 22 0 8 0 0 0 0 7 7 10 21 1 7 0 0 1 0 11 15 5 24 0 0 1 0 0 1 10 10 3 22 1 0 1 0 0 1 13 11 3 23 1 1 1 1 1 1 13 15 2 22 1 8 0 0 0 0 13 12 4 20 1 7 1 0 1 0 13 10 3 20 1 0 1 0 0 1 8 13 5 20 1 8 0 0 0 0 12 13 5 22 0 5 0 0 0 1 13 15 8 22 0 5 0 1 0 1 10 13 4 23 1 7 1 0 0 1 13 13 0.5 20 1 0 0 0 0 0 12 13 0.5 20 1 0 1 0 0 0 15 15 2 21 0 10 1 0 0 1 10 13 6 22 0 6 1 1 0 1 11 8 5 20 0 10 0 0 1 0 12 10 4 19 1 0 1 0 0 1 8 5 2 20 1 0 1 0 1 0 11…What is the appropriate measure of center for these data? O A. Mode OB. Range OC. Mean O D. Median O E. Skew 1525 54 1 5 2 6 5 4 3 19 8 7 6 4 4345656 7 6 9