Homework 4 Question 9 of 30 (1 point) | Question Attempt: 1 of 3 ✓ 2 ✓ 3 ✓ 4 ✓ 5 6 ✓ 7 ✓ 8 = 9 10 11 Given this reaction at 25 °C. PCl5(g) = PC13(g) + Cl₂ (g) Compound Cl₂ (g) PCl₂ (g) PC15 (g) Initial Partial Pressure(atm) 0.306 0.234 0.00330 Use the table of initial partial pressure to find: Note: Reference the Thermodynamic properties of pure substances and Fundamental constants tables for additional information. Part 1 of 2 Round your answer to 1 significant digit. Кр = 21.7 ப x10 Part 2 of 2 ☑ Round your answer to 3 significant digits. Check AG = -7.628 kJ mol ☐ x10 ☐ Save For Later Subr

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Homework 4
Question 9 of 30 (1 point) | Question Attempt: 1 of 3
✓ 2
✓ 3
✓ 4
✓ 5
6
✓ 7
✓ 8
= 9
10
11
Given this reaction at 25 °C.
PCl5(g) = PC13(g) + Cl₂ (g)
Compound
Cl₂ (g)
PCl₂ (g)
PC15 (g)
Initial Partial Pressure(atm)
0.306
0.234
0.00330
Use the table of initial partial pressure to find:
Note: Reference the Thermodynamic properties of pure substances and Fundamental constants tables for additional information.
Part 1 of 2
Round your answer to 1 significant digit.
Кр
=
21.7
ப
x10
Part 2 of 2
☑
Round your answer to 3 significant digits.
Check
AG = -7.628
kJ
mol
☐ x10
☐
Save For Later
Subr
Transcribed Image Text:Homework 4 Question 9 of 30 (1 point) | Question Attempt: 1 of 3 ✓ 2 ✓ 3 ✓ 4 ✓ 5 6 ✓ 7 ✓ 8 = 9 10 11 Given this reaction at 25 °C. PCl5(g) = PC13(g) + Cl₂ (g) Compound Cl₂ (g) PCl₂ (g) PC15 (g) Initial Partial Pressure(atm) 0.306 0.234 0.00330 Use the table of initial partial pressure to find: Note: Reference the Thermodynamic properties of pure substances and Fundamental constants tables for additional information. Part 1 of 2 Round your answer to 1 significant digit. Кр = 21.7 ப x10 Part 2 of 2 ☑ Round your answer to 3 significant digits. Check AG = -7.628 kJ mol ☐ x10 ☐ Save For Later Subr
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