POST) question 17.please answer and show work thank you **Part A**For the reaction\[ \text{3H}_2(g) + \text{N}_2(g) \rightleftharpoons \text{2NH}_3(g) \]at 225 °C the equilibrium constant is \( 1.7 \times 10^2 \). If the equilibrium mixture contains \( 0.14 \, M \, \text{H}_2 \) and \( 0.016 \, M \, \text{N}_2 \), what is the molar concentration of \( \text{NH}_3 \)?Express your answer to two significant figures and include the appropriate units.\[ [\text{NH}_3] = \boxed{\text{Value}} \, \boxed{\text{Units}} \]- **Submit** - **Request Answer**___### Description:This section provides a chemical equilibrium problem where the user must find the molar concentration of \( \text{NH}_3 \) at a given temperature and equilibrium constant. Users are expected to input the correct concentration and units in the provided fields and submit their answer. The problem involves using equilibrium expressions and calculations based on given concentrations of \( \text{H}_2 \) and \( \text{N}_2 \).

Answered: Image /qna-images/answer/cc0a431b-94c6-4250-9cb0-0d9003b183ff.jpg

Part A For the reaction 3H₂(g) + N₂ (g) = 2NH3(g) at 225 °C the equilibrium contant is 1.7 × 10². If the equilibrium mixture contains 0.14 M H₂ and 0.016 MN2, what is the molar concentration of NH3? Express your answer to two significant figures and include the appropriate units. [NH3] = μA Value Submit Request Answer Units ?

Part A For the reaction 3H₂(g) + N₂ (g) = 2NH3(g) at 225 °C the equilibrium contant is 1.7 × 10². If the equilibrium mixture contains 0.14 M H₂ and 0.016 MN2, what is the molar concentration of NH3? Express your answer to two significant figures and include the appropriate units. [NH3] = μA Value Submit Request Answer Units ?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Need help with question #24 Results Trial 1 : Initial Volume = 0 0.5143g=KHP 14.3 = Buret Measurment Trial 2: Initial Volume= 0 0.5615g = KHP 14.1 = Buret Measurement
x 9:22 1/24/2