The US Department of Energy reported that 46% of homes in the USA were heated by natural gas. A randomsample of 300 homes in Oregon found that 146 were heated by natural gas. Test the claim that proportionof homes in Oregon that were heated by natural gas is different from the US reported proportion. Use a 5%significance level. Give answers accurate to at least 3 decimal places.What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)Họ: Select an answerv?H1: Select an answerv ?Based on the hypotheses, find the following:Test Statistic =p-value =Based on the above we choose to Select an answerThe correct summary would be: Select an answerin Oregon heated by natural gas is different than 46%.that the percent of homes

p0 = 46% Number of homes heated by Natural gas , (X)(X) = 146146 Sample Size (n)(n) = 300300…

Họ: Select an answer H1: Select an answer |? Based on the hypotheses, find the following: Test Statistic = p-value = Based on the above we choose to Select an answer | that the percent of homes The correct summary would be: Select an answer in Oregon heated by natural gas is different than 46%.

Họ: Select an answer H1: Select an answer |? Based on the hypotheses, find the following: Test Statistic = p-value = Based on the above we choose to Select an answer | that the percent of homes The correct summary would be: Select an answer in Oregon heated by natural gas is different than 46%.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Problem In 2015 about 60% of college students used Twitter. In a recent study of 100 students, 80…

Q: Image with question is attached. I am asking this question again since it hasn't been answered in 2…

Q: According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the…

A: Suppose p is the true population proportion girls born in Country C.

Q: Find the 30th percentile of the blood pressures. Find the 67th percentile of the blood pressures.…

A: Consider a random variable X which represents the diastolic blood pressures of adult women in the…

Q: c. The test statistic d. The p-value = v = 1.933 x (please show your answer to 3 decimal places.)…

A: Given that Sample size n =393 Favorable cases x =94

Q: What is your p value? Interpret it. No, seriously, interpret it. What does it mean? mean=4.035…

A: P-value:If the null hypothesis is true, then the P-value is the probability of observing at least…

Q: PLEASE DO IN EXCEL The following data were collected in an experiment designed to investigate…

Q: How do I calculate a 95% confidence level for a sample proportion in excel? Meaning, what formula…

A: Given : Confidence level = CL = 95% = 0.95

Q: What size sample should be used to estimate a population proportion within 0.02 with 80% confidence…

A: population proportion = P = 0.02 Level of significance = α = 0.02 population proportion is between…

Q: (V) Conclusion: There is suficient evidence to conclude that the honeymoon location is dependent on…

A: From Part (iii), it can be observed that the level of significance is less than the p-value and the…

Q: Using the table, the predictor "Harsh parenting" had a t test value that equaled 3.465 and its p…

A: The hypothesis is, Null hypothesis: H0: There is no mean difference between the low-mindful…

Q: The heights (to the nearest inch) of 30 males are shown below. Construct a frequency distribution…

A: Given that -

Q: Calcium is essential to tree growth because it promotes the formation of wood and maintains cell…

A: From the provided information, a) The hypotheses are as follow: H0: µ = 0.12 mg/L H1: µ ≠ 0.12 mg/L

Q: Find the standardized test statistic t for a sample with n= 20, x = 13, s= 2.0, and a=0.05 if H: u <…

A: As per guideline expert have to answer first question only.

Q: matchboxes supposed to have average of 40 matches/box, with ? = 7. A random sample of 96 matchboxes…

A: According to guidelines we solve only first three sub parts when given multiple sub parts.

Q: 5. Nancy surveyed 35 randomly selected students in her school about the number of hours they spend…

A: Here out of all students in the school Nancy selected 35 students and obtained a measure 1.2, we…

Q: 4. Sophia scored at the 10th percentile (P10) on exam 1. She claims that this means she outperformed…

A: Given, Sophia scored at the 10th percentile on exam.

Q: An airline company is interested in improving customer satisfaction rate from the 58% currently…

A: Answer:- Given , An airline company is interested in improving customer satisfaction rate from the…

Q: ou want to obtain a sample to estimate a population proportion. Based on previous evidence, you…

A: Given,Sample proportion(p^)=0.331-p^=1-0.33=0.67margin of…

Q: You want to estimate the proportion. What sample size should be obtains to be within 3 % points with…

A: Formula for sample size is,

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data, Less attendance Full attendance 90 96 90 96 60 100 50 99 69 88…

Q: h.com/assess2/?cid=114438&aid=8256974#/skip/11 In a simple random sample of 26 companies, 21 have…

A: Given data number of success , x= 21.0 sample size, n = 26 population…

Q: 18% of all college students volunteer their time. Is the percentage of college students who are…

A: The sample size is 313 in which 47 of them volunteered their time.

Q: For a confidence level of 99% with a sample size of 22, find the t-score. Did not see how to work…

A: The provided information is:

Q: When interpreting the p-value, what did you have to assume was true?

A: Hi! Thank you for the question As per the honour code, We’ll answer the first question since the…

Q: 2.96- Construct a stem-and-leaf diagram for these weights (the photo) 2.96 M&Ms. In the article…

Q: I have a problem that I have worked out the following values for. The mean .85% and the standard…

A: The mean 0.85% the standard deviation is 0.12%.

Q: Is 64.3% a statistic or a parameter? Justify your answer.

A: The objective of the question is to determine whether 64.3% is a statistic or a parameter.

Q: Disney Corporation would like to know what proportion of diners at Disney Springs would prefer to…

A: P=0.8q=0.2M. E. =0.02=0.05

Q: Find the point estimate of p and 96% CI.

A: Given: X: Number of students responded as Yes = 32 n: Total number of students = 100

Q: Which of the following will give the value for the third quartile? a. QUARTILE.INC(array, 0.25)…

A: We have to tell from the given functions which function will give the value of third quartile . We…

Q: What is the multiplier for an interval that estimates the proportion with a. 88% confidence? b.…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: Exam 2 Math 200 Fall 2019-03 7. A random sample of 31 people in a nursing home had a mean systolic…

A: We have to create 90% confidence interval.

Q: The difference between the means for the following items are statistically significant. For which…

A: a.The difference for hugging each other Here the Dating sample is 100 and Married sample is also 100…

Question

The US Department of Energy reported that 46% of homes in the USA were heated by natural gas. A random
sample of 300 homes in Oregon found that 146 were heated by natural gas. Test the claim that proportion
of homes in Oregon that were heated by natural gas is different from the US reported proportion. Use a 5%
significance level. Give answers accurate to at least 3 decimal places.
What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.)
Họ: Select an answerv?
H1: Select an answerv ?
Based on the hypotheses, find the following:
Test Statistic =
p-value =
Based on the above we choose to Select an answer
The correct summary would be: Select an answer
in Oregon heated by natural gas is different than 46%.
that the percent of homes

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1.

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Research Ethics$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

What sample size is needed to give a margin of error of ±5% in estimating a population proportion with 95% confidence?Round your answer up to the nearest integer.sample size = Enter your answer in accordance to the question statement
Hi Can you please fill out the blanks?
open file attached for question
Please show all work so I can understand!
Below is a research question, please answer the following question. After it is solved, you can simply replace the highlighted sentences (the format you should follow, please follow the highlighted sentence format) with the correct answer.
Estimate of the proportion p for a 95% confidence with a sample size ? = 400 and point estimate ?̂= 0.4 Please provide it neatly with indicated given, formula, solution, and answer.
A hospital administrator wants to estimate the proportion of patients whose hospital stay exceeds a week. How many patients should be sampled to estimate the proportion staying more than a week to within 4 percentage points with 90% confidence?
1. A new brand of chocolate bar is being market tested. Four hundred of the new chocolate bars were given to consumers to try. The consumers were asked whether they liked or disliked the chocolate bar. You are given their responses below. A Response Frequency Liked 360 Disliked 40 Total 400