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Research question: It is believed that the proportion of cars with the gas tank filler on the left (driver's side) is same as the proportion with the gas tank filler on right. Formulate a hypothesis, and test it at 5% level of significance. Hint (suggested outline - replace the highlighted area with your observations and calculations): If the proportions are same, then it must be 0.5 Hypothesis: Họ: p = 0.5 H;: p = 0.5 Here p is the population proportion of cars with the gas tank filler on the left. To test this, we can take a random sample of cars, observe the sample proportion (of cars with gas tank filler on the left), and find the p-value of the data to come to a conclusion. Let p be the sample proportion. Under Ho, (5 – 0.5)/(0.5 * 0.5 /n ) = Zstat will have a standard Normal distribution. We conducted this sampling on Monday, October 25, at the Governors State University parking lot A. We observed 38 cars, of which 26 had gas tank fillers on the left. The cars are of different makes and models, and belong to unrelated individuals, hence it is reasonable to assume independence and it is a random sample (if we look at all cars in a dealer's lot, we would not be able to claim it to be a random sample). Also the condition that “n p and n (1- p) should be more than 5" is met. Thus p = 26/38 = 0.6842, Zstat = (0.6842 – 0.5)/ /0.5 • 0.5 /38 = 2.271 p-value = P(Z< - 2.271 ) + P( Z > 2.271) = 0.0231 Since the p-value of the data is below the significance level, we have sufficient evidence (at 5% level) to reject the null hypothesis. We conclude that the proportion of cars with the gas tank filler on the left is not equal to 0.5.

Research question: It is believed that the proportion of cars with the gas tank filler on the left (driver's side) is same as the proportion with the gas tank filler on right. Formulate a hypothesis, and test it at 5% level of significance. Hint (suggested outline - replace the highlighted area with your observations and calculations): If the proportions are same, then it must be 0.5 Hypothesis: Họ: p = 0.5 H;: p = 0.5 Here p is the population proportion of cars with the gas tank filler on the left. To test this, we can take a random sample of cars, observe the sample proportion (of cars with gas tank filler on the left), and find the p-value of the data to come to a conclusion. Let p be the sample proportion. Under Ho, (5 – 0.5)/(0.5 * 0.5 /n ) = Zstat will have a standard Normal distribution. We conducted this sampling on Monday, October 25, at the Governors State University parking lot A. We observed 38 cars, of which 26 had gas tank fillers on the left. The cars are of different makes and models, and belong to unrelated individuals, hence it is reasonable to assume independence and it is a random sample (if we look at all cars in a dealer's lot, we would not be able to claim it to be a random sample). Also the condition that “n p and n (1- p) should be more than 5" is met. Thus p = 26/38 = 0.6842, Zstat = (0.6842 – 0.5)/ /0.5 • 0.5 /38 = 2.271 p-value = P(Z< - 2.271 ) + P( Z > 2.271) = 0.0231 Since the p-value of the data is below the significance level, we have sufficient evidence (at 5% level) to reject the null hypothesis. We conclude that the proportion of cars with the gas tank filler on the left is not equal to 0.5.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Research question: It is believed that the proportion of cars with the gas tank filler on the left (driver's side) is same as the proportion with the gas tank filler on right. Formulate a hypothesis, and test it at 5% level of significance. Hint (suggested outline – replace the highlighted area with your observations and calculations): If the proportions are same, then it must be 0.5 Hypothesis: Họ: p = 0.5 H;: p + 0.5 Here p is the population proportion of cars with the gas tank filler on the left. To test this, we can take a random sample of cars, observe the sample proportion (of cars with gas tank filler on the left), and find the p-value of the data to come to a conclusion. Let p be the sample proportion. Under Ho, (p – 0.5) (0.5 * 0.5 /n ) = Zstat will have a standard Normal distribution. We conducted this sampling on Monday, October 25, at the Governors State University parking lot A. We observed 38 cars, of which 26 had gas tank fillers on the left. The cars are of different makes and models, and belong to unrelated individuals, hence it is reasonable to assume independence and it is a random sample (if we look at all cars in a dealer's lot, we would not be able to claim it to be a random sample). Also the condition that "n p and n (1- p) should be more than 5" is met. Thus p = 26/38 = 0.6842, Zstat = (0.6842 – 0.5)/ J0.5 * 0.5 /38 = 2.271 p-value = P( Z< - 2.271 ) + P( Z > 2.271) = 0.0231 Since the p-value of the data is below the significance level, we have sufficient evidence (at 5% level) to reject the null hypothesis. We conclude that the proportion of cars with the gas tank filler on the left is not equal to 0.5.
Transcribed Image Text:Research question: It is believed that the proportion of cars with the gas tank filler on the left (driver's side) is same as the proportion with the gas tank filler on right. Formulate a hypothesis, and test it at 5% level of significance. Hint (suggested outline – replace the highlighted area with your observations and calculations): If the proportions are same, then it must be 0.5 Hypothesis: Họ: p = 0.5 H;: p + 0.5 Here p is the population proportion of cars with the gas tank filler on the left. To test this, we can take a random sample of cars, observe the sample proportion (of cars with gas tank filler on the left), and find the p-value of the data to come to a conclusion. Let p be the sample proportion. Under Ho, (p – 0.5) (0.5 * 0.5 /n ) = Zstat will have a standard Normal distribution. We conducted this sampling on Monday, October 25, at the Governors State University parking lot A. We observed 38 cars, of which 26 had gas tank fillers on the left. The cars are of different makes and models, and belong to unrelated individuals, hence it is reasonable to assume independence and it is a random sample (if we look at all cars in a dealer's lot, we would not be able to claim it to be a random sample). Also the condition that "n p and n (1- p) should be more than 5" is met. Thus p = 26/38 = 0.6842, Zstat = (0.6842 – 0.5)/ J0.5 * 0.5 /38 = 2.271 p-value = P( Z< - 2.271 ) + P( Z > 2.271) = 0.0231 Since the p-value of the data is below the significance level, we have sufficient evidence (at 5% level) to reject the null hypothesis. We conclude that the proportion of cars with the gas tank filler on the left is not equal to 0.5.
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