***Hint from professor:  Please remember that in translation the summation of moments of forces is always equal to the moment of the m a_G vector, not zero. The m a_G vector originates at G and the sign of the moment of this vector only depends on whether the moment is clockwise or counterclockwise, never on whether a_G itself is positive or negative. The normal force in problem 1 is never zero and there is no need to use any angle for the force P because the horizontal and vertical components of this force may be determined directly using summations of forces and moments.  Also remember that one may take moments about any point. In practice, one selects a moment point that eliminates the moments of as many unknown forces as possible.

icon
Related questions
Question

***Hint from professor: 

Please remember that in translation the summation of moments of forces is always equal to the moment of the m a_G vector, not zero. The m a_G vector originates at G and the sign of the moment of this vector only depends on whether the moment is clockwise or counterclockwise, never on whether a_G itself is positive or negative.

The normal force in problem 1 is never zero and there is no need to use any angle for the force P because the horizontal and vertical components of this force may be determined directly using summations of forces and moments.  Also remember that one may take moments about any point. In practice, one selects a moment point that eliminates the moments of as many unknown forces as possible.

1) A loaded wheelbarrow is pulled to the left with an acceleration a = 2 m / s2 by a force P. In this motion,
the wheelbarrow does not rotate and the force of friction as well as the effect of the rotation of the wheel
may be neglected. The combined mass of the wheelbarrow and its load is 250 kg with center of mass at
G. For this instant, determine the horizontal and vertical components of the force P and the normal
reaction at B.
a
P
G
60 cm
50 cm
1 m
20 cm
Transcribed Image Text:1) A loaded wheelbarrow is pulled to the left with an acceleration a = 2 m / s2 by a force P. In this motion, the wheelbarrow does not rotate and the force of friction as well as the effect of the rotation of the wheel may be neglected. The combined mass of the wheelbarrow and its load is 250 kg with center of mass at G. For this instant, determine the horizontal and vertical components of the force P and the normal reaction at B. a P G 60 cm 50 cm 1 m 20 cm
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer