Problem 5: An object of mass m has these three forces acting on it (there is no normal force,"no surface"). F = 3 N, F2 = 10 N, and F3 = 5 N. When answering the questions below, assume thex-direction is to the right, and they-direction is straight upwards.F,FWhat is the net force in component form, in terms of F1, F2, F3, and the unit vectors i and jF =78HOMEaF|ij45yd.F11 | 23F2F3+| -ENDhPvol BACKSPACEDEL CLEARSubmitHintFeedbackI give up!What is the magnitude of the net force, in newtons?What is the angle e, in degrees, of the net force, measured from the +x-axis? Enter an angle between -180° and 180°.What is the magnitude, Ja of the acceleration, in meters per square second, if the block has a mass of 8.9 kg?

a) F = F1(-j) + F2 i + F3 (-i) F = -3j + 10i - 5i = 5i -3j b) magnitude of net force =…

Answered: Problem 5: An object of mass m has…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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HW1.4. 2D Moment resultant Two forces lying in the x-y plane are defined by their magnitudes and direction angles, as shown in the figure below. Force F₁ has a magnitude F₁ = 360 N, an angle 0₁ = 109°, and acts at point A (310, 0) mm. Force F₂ has a magnitude F₂ = 270 N, an angle 02 = 56°, and acts at point B = (0,385) mm. Determine the total moment about point O due to these two forces. Remember to follow the standard sign convention for clockwise (-) and counter-clockwise (+) moments. y B 10 02 F₂ F₁ A 0₁ X TEGINGEN
A rocket takes off from Earth's surface, accelerating straight up at 45.2m/s2. Calculate the normal force (in N) acting on an astronaut of mass 85.9kg, including his space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.) N
A horizontal (F = 12N) force pushes a block weighing (F, = 5.0N) against a vertical wall. The coefficient of static friction between the wall and the block is µg = 0.60, and the coefficient of kinetic friction is µk = 0.40. Assume that the block is not moving initially. %3D a) Draw a free body diagram of the block in the figure. b) What is the normal force (in unit vector notation) on the block from the walI? c) Will the block move? Please give your reason with calculation. d) In unit-vector notation, what is the force on the block from the wall?
Block 1 with mass 66 kg is sitting on a horizontal frictionless surface as shown below. It is attached to a string of negligible mass that goes over a pulley with negligible mass and negligible friction. The other end of the string is attached to block 2 with mass 254 kg. Find the magnitude of the common acceleration of the two blocks! A. a = 37.75 m/s² B. a = 13.25 m/s² C. a = 5.76 m/s² D. a = 0 m/s² E. a = 7.79 m/s² 1 2
Part A Make a free-body diagram of the box B. Draw the force vectors with their tails at the dot. Part B Make a free-body diagram of the box A. Draw the force vectors with their tails at the dot.
Tommy is working on a physics problem and asks his friend Sarah to check his work. He is to draw a free body diagram for a man walking to the left and comes up with the following: He reasons, “The man is walking to the left, so the force of friction is acting in the opposite direction. The normal force should be opposite and equal to that of the gravitational force.” Is Tommy correct with his diagram and reasoning? If so, explain. If not, what mistake did he make? Communication throughout the test will also be evaluated on 1) rounding using significant digits, 2) proper use of units, 3) organization and neatness, and 4) showing all work
Two Blocks having mass m=11.0 kg are connected by a light string passing through two pulleys as shown. The block on the left is resting on an inclined plane of angle 0=45.0° . The pulleys and the planes on which the blocks are resting are frictionless. The blocks are released from rest and allowed to move freely. a. Draw the free body diamgrams for each block and then write down newton's second law of motion for each one separately. b. Find the acceleration of the blocks and the tension in the string.
d. Force is a vector quantity and thus has both a magnitude and a direction. A vector can be represented graphically by a line drawn to scale in the direction of the line of action of the force. To distinguish between vector and scalar quantities, various ways are used. Identify and explain threeof these ways.
A cardboard box rests on the floor of an elevator. The box has a mass m = 2.75 kg and the elevator has an upward acceleration of a. a. Write an expression for the sum of the forces acting on the box in the y-direction, ΣFy, given that up is the positive y-direction. Your answer should be in terms of FN, m, and g. b. Write an expression for the normal force, FN, that the block experiences in terms of the elevator's acceleration, the block's mass, and the acceleration of gravity. c. If the elevator's acceleration has a magnitude of g in the downward direction, what would the normal force, FN1 be in Newtons? d.If the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force FN2 be in Newtons?
A teenager of mass m1 = 56 kg pushes backwards against the ground with his foot as he rides his skateboard. This exerts a horizontal force of magnitude F foot = = 18.5 N. The skateboard has m2 = 2.6 kg. a. Write an expression for the magnitude of the horizontal component of force that the ground exerts on the teenagers foot, F ground. b. Write an expression in terms to given quantities for the magnitude of the skateboard acceleration, a , while the teenager is pushing backwards on the ground? c. What is the numerical value of the magnitude of the acceleration, a, in m/s square?
Please don't provide handwritten solution....
Newton's first law states that: Group of answer choices Ia. n the absence of any net force acting on it, a mechanical system is necessarily at rest. b. In the absence of a non-zero net force acting on it, a mechanical system keeps moving in the same direction at the same speed (including the case v=0). c. For any pair A/B of objects interacting with one another, the force of A acting on B is the equal-opposite of the force of B acting on A. d. The rate of change of the velocity of a system is proportional to the net force acting on it.

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