A quokka (a ridiculously cute small marsupial – look it up on Google) of height 30 cm stands on the ground 2 m to the left of a wall with a small pinhole at the height of 1 m above ground level. An image of the quokka appears on a tall screen 6 m to the right of the wall. Draw and upload a diagram (with labelled distances) and trace the rays from the feet and the head as they travel to the screen.

A quokka (a ridiculously cute small marsupial – look it up on Google) of height 30 cm stands on the ground 2 m to the left of a wall with a small pinhole at the height of 1 m above ground level. An image of the quokka appears on a tall screen 6 m to the right of the wall. Draw and upload a diagram (with labelled distances) and trace the rays from the feet and the head as they travel to the screen.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: Shown in the figure below is a system containing two lenses and an object. The focal lengths of the…

A: Lens formula: The lens formula is applicable for both convex and concave lenses. The equation…

Q: 1.1 cm-tall object is 13 cm in front of a converging lens that has a 35 cm focal length. Calculate…

Q: If a beam enters from air (n = 1.00) at an angle of 45 degrees into a mystery substance and exits at…

Q: A submarine is 285 m horizontally from the shore of a freshwater lake and 111 m beneath the surface…

Q: Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each…

A: From the question, it is given that- Object distance from lens: u=23 cmFocal length of lens f=4.2 cm

Q: Spherical refracting surfaces. When an object is placed 9.3 cm in front of a spherical refracting…

Q: A student is examining various objects with a diverging lens. The lens has a focal length of…

A: Focal length (f) = -17 cm a) Object distance (p) = 34 cm

Q: m of a horizontal line passing through a vertical lens. Along the horizontal line, from left to…

A: Given:- The object distance is u = -10 cm the focal leingth of the lens f = -20 cm find:- The…

Q: A person with 20/20 vision can see what an average individual can see on an eye chart when they are…

Q: Re A woman can produce sharp images on her retina only of objects that are from 150 cm to 25 cm from…

Q: A diverging lens has an object placed 30 cm from the optical center of the lens. A Virtual image is…

Q: (a) Draw a ray diagram to find the location of the image. Be sure to include the image in your…

Q: An object of height 3.2 cm is placed at 22 cm in front of a diverging lens of focal length, f = - 16…

A: The height of the object is given as, ho=3.2 cm, The distance between the object and the diverging…

Q: The local county fair this summer has a challenge with a winning prize of $250. You have to throw a…

Q: A 2.0-cmcm-diameter spider is 2.4 mm from a wall. Determine the focal length f of a lens that will…

Q: I'm going to install a placard on the school bulletin board. The placard is 2 meters long and the…

A: Given:-

Q: d A person with a height of 1.4 meters stands at the edge of a lake that is 2.8 meters deep, d = 2.8…

Q: Suppose we place a Sharpie in front of a lens. The Sharpie has length 18 cm and is oriented at a 45°…

Q: two spherical mirrors

A: The focal length of a spherical mirror is given by the following equation:f = R / 2 where f is the…

Q: A 2 centimeter tall candle flame is 2 meters from a wall. You happen to have a lens with a focal…

Q: A 1.5 cmcm high object is located 30 cmcm from a diverging lens, whose focal length is 11 cmcm .…

A: Given: Height of the object, h=1.5 cm Object distance from lens, u=30 cm Focal length of lens, f=11…

Q: A student is examining various objects with a diverging lens. The lens has a focal length of…

Q: 4. A projector has a 0.010m tall LCD display, which is projected onto a screen by its lens. The…

A: The magnification of lens, m = h'/h = v/u Where m= magnification h’= height of the image h = height…

Q: An object that is 2.0 cm tall is located 5.0 cm behind the vertex of a converging lens with a focal…

Q: Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each…

A: Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts…

Q: Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each…

A: We recall that for a diverging (D) lens, the focal length value should be negative ( f=–14cm).

Q: Spherical refracting surfaces. When an object is placed 8.8 cm in front of a spherical refracting…

A: The relation between the object distance p, image distance i, and the radius of curvature r of a…

Q: Part A: State the characteristics of the image formed by a converging lens when the object is…

A: As shown in the figure above, when the object is placed in front of the focal point, the refracted…

Q: A convex lens has a focal length of 8 cm. An object that is 4 cm tall is placed at unknown distance…

A: Given focal length f=+8cm Since image is virtual therefore it will form on the same side of the lens…

Q: Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each…

Q: A beam of light enters from air into a slab of glass (nglass=1.5) along a surface tilted at a 45…

Question

A quokka (a ridiculously cute small marsupial – look it up on Google) of height 30 cm
stands on the ground 2 m to the left of a wall with a small pinhole at the height of 1 m
above ground level. An image of the quokka appears on a tall screen 6 m to the right
of the wall.
Draw and upload a diagram (with labelled distances) and trace the rays from the feet
and the head as they travel to the screen.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Follow-up Questions

Read through expert solutions to related follow-up questions below.

Follow-up Question

Hi, I was wondering how I could work out what height the quokka's feet are above the ground? Thanks

Solution

by Bartleby Expert

SEE SOLUTION

Similar questions

Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.
Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) Lens i m R/V I/NI Side +14 C, 24 (a) Number Units (b) Number i Units (c) (d) (e) > >
A 2.1-cm-tall object is 30 cm to the left of a lens with a focal length of 15 cm. A second lens with a focal length of -5 cm is 45 cm to the right of the first lens. Calculate the distance between the first image and the second lens. Calculate the image height.
A blue whale eyeball may be taken as a sphere that is about 15 cm in diameter. Assuming that it is filled with material with an index of refraction of 1.5, where would the image form for an object (in water) that is very far away? Just consider the initial image formed by refraction through the front surface. Select answer from the options below 15 cm behind the back of the eye 7.5 cm behind the front surface of the eye 15 cm behind the front surface of the eye Approximately 30 cm behind the back of the eye Approximately 50 cm behind the back of the eye
Famous jeweler Gabi Tolkowsky is looking at a 3.0-cm-tall perfect oval-shaped diamond through a thin lens. The diamond is 20.0 cm behind the lens, and the distance between its upright image and the lens is 40.0 cm. What is the focal length of the lens? Is it converging or diverging? How tall is the image?   PLEASE PLEASE draw a ray diagram and define variables
A diverging lens has a focal distance of f=0.2 cm. If an object is placed 0.1cm away, What is the image distance? Is the image real or virtual? What is the magnification?
You are in a boat watching a shark swim below you. From a measuring stick on the side of the boat you can tell it is 6 m down. How deep does its image appear to be? n=1 for air, n=1.33 for water.
A 3.0 cm tall object is positioned 15.5 cm from a converging lens. The focal length of the lens is 10.5 cm. What is the distance to the image? What is the magnification of the image? What is the height of the image? Is the image real or virtual? Is the image inverted or upright?
The image of the Moon is formed by a concave mirror (aka telescope) whose radius of curvature is 9.62m at a time when the Moon's angular diameter is 0.523degrees. What is the diameter (magnitude only) of the image (cm) of the moon? HINT: What is the property of the rays coming from one point on the edge of the Moon (think of the moon as being infinitely far away)? Where do those rays converge to form an image of that point? Use the small angle approximation: sin(x)=tan(x)=x for |x|<<1, when x is measured in radians.