Hg²+ + 2 e → HgHg2* + 2 e → 2 HgHg,Br2 + 2 e –→ 2 Hg + 2 BrMnO4 + 4 H* + 3 e¯ → MNO2 + 2 H2O E° = +1.68 VPb + 2 e –→ PbSn²* + 2 e → SnE° = +0.851 V2+E° = +0.797 VE° = -0.126 VE° = +0.139 VE° = –0.02 VCalculate the solubility product for Hg2Br2.

Answered: Image /qna-images/answer/bc8a0a46-aa09-4b0b-8c44-6ac497e1f7bf.jpg

Hg* + 2 e → Hg Hg22* + 2 e → 2 Hg Hg,Br2 + 2 e -→ 2 Hg + 2 Br MnO4 + 4 H* + 3 e MnO2 + 2 H2O E° = +1.68 V Pb2* + 2 e → Pb Sn2* + 2 e → Sn E° = +0.851 V E° = +0.797 V E° = -0.126 V E° = +0.139 V E° = -0.02 V Calculate the solubility product for Hg2Br2.

Hg* + 2 e → Hg Hg22* + 2 e → 2 Hg Hg,Br2 + 2 e -→ 2 Hg + 2 Br MnO4 + 4 H* + 3 e MnO2 + 2 H2O E° = +1.68 V Pb2* + 2 e → Pb Sn2* + 2 e → Sn E° = +0.851 V E° = +0.797 V E° = -0.126 V E° = +0.139 V E° = -0.02 V Calculate the solubility product for Hg2Br2.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

Hg²+ + 2 e → Hg
Hg2* + 2 e → 2 Hg
Hg,Br2 + 2 e –→ 2 Hg + 2 Br
MnO4 + 4 H* + 3 e¯ → MNO2 + 2 H2O E° = +1.68 V
Pb + 2 e –→ Pb
Sn²* + 2 e → Sn
E° = +0.851 V
2+
E° = +0.797 V
E° = -0.126 V
E° = +0.139 V
E° = –0.02 V
Calculate the solubility product for Hg2Br2.

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