HERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) → 2Q2 (g) + 6J2X (I) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) → Q2X (g) (Round off final answer to ONE decimal place) AH = -1067.7 kJ AH = -1509 kJ Round your answer to 1 decimal place.

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HERMODYNAMICS: Given the following hypothetical thermochemical equations:
2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1)
4QJ3 (g) + 3X2 (g) → 2Q2 (g) + 6J2X (I)
Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) → Q2X (g)
(Round off final answer to ONE decimal place)
AH = -1067.7 kJ
AH = -1509 kJ
Round your answer to 1 decimal place.
Transcribed Image Text:HERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (1) 4QJ3 (g) + 3X2 (g) → 2Q2 (g) + 6J2X (I) Calculate the value of AH (in kJ) for the reaction: Q2 (g) + ½ X2 (g) → Q2X (g) (Round off final answer to ONE decimal place) AH = -1067.7 kJ AH = -1509 kJ Round your answer to 1 decimal place.
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