Here's the cheat-sheet below.tt nontaster (homozygous recessive): single band at 221bpTT taster (homozygous dominant): two bands (177bp and 44bp)Tt taster (heterozygous): 3 bands representing both alleles (221bp, 177bp, 44bp)MARKER tt nontasterTT tasterU DTt tasterU DMARKERPBR322/U D100 bpladderBstNI1857 bp929 bp383 bp121 bp221 bp177 bp44 bpprimer dimerif present)This figure shows you expected results for the 3 possible genotypes. The U isfor "undigested', meaning what you see before using the restriction enzyme. TheD is for digested.Q8) In the figure above, which was the BETTER ladder to use for this experiment?PBR322/BstNI or the 100 bp ladder?

The sequence of a "DNA segment" can be used for a variety of purposes. The sequence of amino acids…

Here's the cheat-sheet below. tt nontaster (homozygous recessive): single band at 221bp TT taster (homozygous dominant): two bands (177bp and 44bp) Tt taster (heterozygous): 3 bands representing both alleles (221bp, 177bp, 44 bp) MARKER tt nontaster TT taster U D Tt taster MARKER PBR322/ U D 100 bp ladder U 1857 bp 1058 bp 383 bp 121 bp 221 bp 177 bp 44 bp primer dimer if present) This figure shows you expected results for the 3 possible genotypes. The U is for 'undigested', meaning what you see before using the restriction enzyme. The Dis for digested. Q8) In the figure above, which was the BETTER ladder to use for this experiment? PBR322/BstNI or the 100 bp ladder?

Here's the cheat-sheet below. tt nontaster (homozygous recessive): single band at 221bp TT taster (homozygous dominant): two bands (177bp and 44bp) Tt taster (heterozygous): 3 bands representing both alleles (221bp, 177bp, 44 bp) MARKER tt nontaster TT taster U D Tt taster MARKER PBR322/ U D 100 bp ladder U 1857 bp 1058 bp 383 bp 121 bp 221 bp 177 bp 44 bp primer dimer if present) This figure shows you expected results for the 3 possible genotypes. The U is for 'undigested', meaning what you see before using the restriction enzyme. The Dis for digested. Q8) In the figure above, which was the BETTER ladder to use for this experiment? PBR322/BstNI or the 100 bp ladder?

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Pedigree information regarding the incidence of Tay-Sachs within a family is depicted above. The row below that indicates the genotypes of individuals II-1, II-2, and III-1 is Select one: a. II-1 II-2 III-1 Aa Aa aa b. II-1 II-2 III-1 XAY XAXA XaXa
Shown below is a pedigree for a completely penetrant trait called Adams syndrome in which babies are born blind. This trait occurs when an allele of the adams gene is associated with ≥200 tandem trinucleotide repeats (the normal number is 10). First cousins, III-1 and III-2 married and their first child (IV-1) was blind. For their next child, they decided to do in vitro fertilization with III-1's sperm and III-2's eggs to generate six embryos (labeled E1-6). When each embryo contained eight cells, a single cell was removed and genomic DNA was isolated. PCR reactions using primers that flank the trinucleotide repeat region were then performed and the resulting fragments were fractionated on an agarose gel. PCR reactions using genomic DNA from III-1, III-2 and IV-1 were included as controls. The DNA was visualized using a fluorescent dye and the gel is shown below. Based on this information, select the best answer from the list to the questions below. || E1 = embryo 1 IV E1 E2 E3 E4 E5…
Hi, I'm having some trouble with this practice problem from my study guide. If anyone can explain it it would be very helpful! Brindle coloration is a black and brown striping pattern in some dogs. This fur coloration is controlled by different alleles at a single autosomal locus. There are three alleles, KB, kbr and ky. The KB allele is dominant over the other two alleles and produces a solid black color. The allele kbr produces the brindle color pattern and is dominant over the ky allele, which produces yellow fur. Give the genotypes of the parents and offspring in each cross. P: black X yellow; F1: ½ brindle and ½ black P: black X brindle; F1: ½ black, ¼ brindle and ¼ yellow P: brindle X yellow; F1: 100% brindle
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Duchenne’s muscular dystrophy (DMD) is an X-linked disease that causes progressive muscle weakness and is often fatal. “XD” represents the wild type allele, and “Xd,” the mutant allele. Jonah is XDXd Y and his brother Pete is Xd Y. Jonah and Pete BOTH have DMD of equal severity and phenotypes. You might have thought Jonah’s DMD would be less severe given his genotype. To better understand the situation, you investigate Jonah’s Xist chromosome region in his defective muscle cells. Which of the following is consistent with his phenotype? (Select all that apply.) The Xd-containing chromosome is inactive in defective muscle cells. The XD-containing chromosome has a methylated Xist promoter. The XD-containing chromosome has an unmethylated Xist promoter. The Xd-containing chromosome is active in defective muscle cells.
Can you please not type the answer can you write it on a paper
determine if the possible alleles are complete dominate, incomplete dominance, or codominance.
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The Answer is "A" but can you tell me why the answer isn't also "C"