Here is a sketch of a \(2p_x\) orbital:![2px orbital sketch](#)This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse.Suppose an atom with its nucleus at the origin has an electron in a \(2p_x\) orbital. Complete each row of the table below by deciding how \(P_A\), the probability of finding the electron at point A, compares to \(P_B\), the probability of finding the electron at point B.| point A | point B | compare \(P_A\) to \(P_B\) ||----------------------------------------------|----------------------------------------------|---------------------------------------|| 100 pm **behind** the nucleus, along the +y axis. | 100 pm **above** the nucleus, along the +z axis. | ○ \(P_A < P_B\) ○ \(P_A = P_B\) ○ \(P_A > P_B\) || 100 pm **below** the nucleus along the -z axis. | 100 pm **in front of** the nucleus, along the -y axis. | ○ \(P_A < P_B\) ○ \(P_A = P_B\) ○ \(P_A > P_B\) || 100 pm to the **left** of the nucleus, along the -x axis. | 100 pm to the **right** of the nucleus, along the +x axis. | ○ \(P_A < P_B\) ○ \(P_A = P_B\) ○ \(P_A > P_B\) |Select the appropriate comparison for each scenario.

Answer:Orbital is a space around the nucleus in which probability of finding an electron will be…

Here is a sketch of a 2px orbital: ▬▬▬▬▬▬▬▬▬▬ I X This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P4, the probability of finding the electron at point A, compares to P3, the probability of finding the electron at point B. point A 100 pm behind the nucleus, along the +y axis. 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. point B 100 pm above the nucleus, along the +z axis. 100 pm in front of the nucleus, along the -y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB P, < P B A O O O P₁ = P₁ PB A P < P B PA P₁ = P, B P. > P. A PA PB

Here is a sketch of a 2px orbital: ▬▬▬▬▬▬▬▬▬▬ I X This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P4, the probability of finding the electron at point A, compares to P3, the probability of finding the electron at point B. point A 100 pm behind the nucleus, along the +y axis. 100 pm below the nucleus along the -z axis. 100 pm to the left of the nucleus, along the -x axis. point B 100 pm above the nucleus, along the +z axis. 100 pm in front of the nucleus, along the -y axis. 100 pm to the right of the nucleus, along the +x axis. compare PA to PB P, < P B A O O O P₁ = P₁ PB A P < P B PA P₁ = P, B P. > P. A PA PB

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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O ELECTRONIC STRUCTURE Interpreting the angular probability distribution of an orbital This sketch is about 800 pm wide. The coordinate (x, y, and z) axes are also shown. You can rotate the sketch for a better view of the orbital by dragging the slider with your mouse. i II IIIII Suppose an atom with its nucleus at the origin has an electron in a 2p, orbital. Complete each row of the table below by deciding how P, the probability of finding the electron at point A, compares to PR, the probability of finding the electron at point B. point A point B compare PA to P P 100 pm in front of the nucleus, along the -y axis. 100 pm to the left of the nucleus, along the -x axis. O P. = P. O P, > P 100 pm behind the nucleus, along the +y axis. 100 pm below the nucleus along the -z axis. O P, = P O P,> P O P, P, Explanation Check O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility MacBook Pro
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