Here are summary statistics for the weights of Pepsi in randomly selected cans: n = 36, x=0.82412 lb, s= 0.00573 lb. Use a confidence level of 95% to complete parts (a) through (d) below. a. Identify the critical value to/2 used for finding the margin of error. ta/2= = 2.03 (Round to two decimal places as needed.) b. Find the margin of error. E= 0194 lb (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ. lb<μ

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Here are summary statistics for the weights of Pepsi in randomly selected cans:  
- Sample size \( n = 36 \)  
- Sample mean \( \bar{x} = 0.82412 \) lb  
- Sample standard deviation \( s = 0.00573 \) lb  

Use a confidence level of 95% to complete parts (a) through (c) below.

---

a. **Identify the critical value \( t_{\alpha/2} \) used for finding the margin of error.**  
\( t_{\alpha/2} = 2.03 \)  
(Round to two decimal places as needed.)

b. **Find the margin of error.**  
\( E = 0.00194 \) lb  
(Round to five decimal places as needed.)

c. **Find the confidence interval estimate of \(\mu\).**  
( \(0.82218 \) lb < \(\mu\) < \(0.82606\) lb )  
(Round to five decimal places as needed.)
Transcribed Image Text:Here are summary statistics for the weights of Pepsi in randomly selected cans: - Sample size \( n = 36 \) - Sample mean \( \bar{x} = 0.82412 \) lb - Sample standard deviation \( s = 0.00573 \) lb Use a confidence level of 95% to complete parts (a) through (c) below. --- a. **Identify the critical value \( t_{\alpha/2} \) used for finding the margin of error.** \( t_{\alpha/2} = 2.03 \) (Round to two decimal places as needed.) b. **Find the margin of error.** \( E = 0.00194 \) lb (Round to five decimal places as needed.) c. **Find the confidence interval estimate of \(\mu\).** ( \(0.82218 \) lb < \(\mu\) < \(0.82606\) lb ) (Round to five decimal places as needed.)
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